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amid [387]
3 years ago
6

The dimensions of a block that weighs 30 N are 0.23 mx 0.12 mx 0.075 m.

Physics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:25000/23 N/M^2

Explanation:

P=f/A=30/(0.23×0.12)=25000/23

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Answer:

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Using equilibrium of electric force on third charge

\frac{kq_{2}q}{d^{2}} = \frac{kq_{1}q}{(r+d)^{2}}

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