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3 years ago

A table is pushed it 15 metre across a room with the force of 50N.what is the work done?

Physics

1 answer:

kiruha [24]3 years ago

6 0

Answer:

W=f*d

= 50 * 15

=750 J

Therefore, the work done is 750 joule( J)

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Hey there!

eimsori [14]

The time taken for the two balls to hit each other is 8 s.

The given parameters:

Acceleration of the rocket, a = 2 m/s²
Length of the chamber, s = 4 m
Speed of the first ball, = V1 = 0.3 m/s
Speed of the second ball, V2 = 0.2 m/s

The time taken for the two balls to hit each other is calculated by applying relative velocity formula as shown below;

$(V_1 - (-V_2) )t = s\\\\(V_1 + V_2) t = s\\\\(0.3 + 0.2) t = 4\\\\0.5t = 4\\\\t = \frac{4}{0.5} \\\\t = 8 \ s$

Thus, the time taken for the two balls to hit each other is 8 s.

Learn more about relative velocity here: brainly.com/question/17228388

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2 years ago

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A table is pushed it 15 metre across a room with the force of 50N.what is the work done? ​

A table is pushed it 15 metre across a room with the force of 50N.what is the work done?