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PSYCHO15rus [73]
3 years ago
5

Please he with c Please I swear I am crying

Chemistry
2 answers:
Marina CMI [18]3 years ago
8 0

Answer: 6 neutrons but im sorry idk how to explain it or work it out :(

Explanation:

good luck tho!

Helga [31]3 years ago
7 0
Step 1: Subtract the atomic number from the mass number
Step 2: 12 - 6 = 6
Therefore the number of neutrons is 6
Because the number of neutrons is equal to the difference between the mass number of the atom and the atomic number
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The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table b
denis-greek [22]

Answer:

220.42098 amu

Explanation:

(220 .9 X  .7422) + (220 X .0.1278) + (218.1 X 0.13) =     220.42098 amu

These are weighted averages.

So, we will take mass of one and multiply by abundance percentage that is provided and add them together.

In order to calculate the  average atomic mass, we have to convert the percentages of abundance to decimals. So, you get

(220 .9 X  .7422) + (220 X .0.1278) + (218.1 X 0.13) =     220.42098 amu

6 0
3 years ago
Propane(C3H8) combusts with oxygen gas. If you start with 15 grams of Propane, how many grams of carbon dioxide will be produced
skelet666 [1.2K]
<em>mC₃H₈: 44 g/mol</em>
<em>mCO₂: 44 g/mol</em>
---------------------

C₃H₈ + 5O₂ ----> 3CO₂ + 4H₂O
44g                    (44·3)g


44g C₃H₈ ------ 132g CO₂
15g C₃H₈ ------ X
X = (15×132)/44
<u>X = 45g CO₂
</u>

_____
:)

4 0
3 years ago
Why melting point of Fe in blast furnace is lower than ellingham?
Kaylis [27]

Answer:

Because they are different oxides.

Explanation:

In both processes they are involve Iron Oxides, but in the case of Ellingham diagrams, it is consider the Iron in combination with oxygen to form FeO, so the melting point is around 1600  ºC. In the case of blast furnace, the Fe that is present in the ores, are primary the hematite (Fe2O3) and the magnetite (Fe3O4).

6 0
3 years ago
***URGENT PLEASE**** Select all of the bases listed *
Masteriza [31]

Answer:

NaOH (a strong base)

Ammonia ( weak base )

6 0
3 years ago
A 13-gram rubber stopper is attached to a 0.93-meter
makkiz [27]
<h3>Answer:</h3>

The centripetal acceleration is 26.38 m/s²

<h3>Explanation:</h3>

We are given;

  • Mass of rubber stopper = 13 g
  • Length of the string(radius) = 0.93 m
  • Time for one revolution = 1.18 seconds

We are required to calculate the centripetal acceleration.

To get the centripetal acceleration is given by the formula;

Centripetal acc = V²/r

Where, V is the velocity and r is the radius.

Since time for 1 revolution is 1.18 seconds,

Then, V = 2πr/t, taking π to be 3.142 ( 1 revolution = 2πr)

Therefore;

Velocity = (2 × 3.142 × 0.93 m) ÷ 1.18 sec

             = 4.953 m/s

Thus;

Centripetal acceleration = (4.953 m/s)² ÷ 0.93 m

                                        = 26.38 m/s²

Hence, the centripetal acceleration is 26.38 m/s²

6 0
3 years ago
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