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vekshin1
2 years ago
13

Calculate the weight of your energy car if it has a mass of 233.85 kg.

Physics
1 answer:
lianna [129]2 years ago
3 0

Explanation:

'gerfe4egd4gwdrferdfw14589u99y999q EP and it's not the same thing to say about this is a good day for the next few weeks of age or something else I would have to do it for you and your friends to be the first to see the new album and I am a big deal to the world is not the same thing to say about this one for you and I am a big deal to me that he was the first to see you in a few years back and forth to see the world is not a fan and a few years back and I have to be the best way possible for the next few days later and the other side is the only thing that you can get it right here is the only thing I can get it right here is a great time to get a free download of my life

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What is the kinetic energy of a 2000 kilogram boat moving at 5m/sec?
Tanya [424]
<span>Hello!
KE=1/2MV^2 where M=2000 kg and V=5 m/s .5(2000)*(5^2)=25000 J</span>
4 0
3 years ago
At NASA's Zero Gravity Research Facility in Cleveland, Ohio, experimental payloads fall freely from rest in an evacuated vertica
Diano4ka-milaya [45]

Answer:

(a). Energy is 64,680 J

(b) velocity is 51.43m/s

(c) velocity in mph is 115.0mph

Explanation:

(a).

The potential energy P of the payload of mass m is at a vertical distance h is  

P =mgh.

Therefore, for the payload of mass m = 50kg at a vertical distance of h = 132 m, the potential energy is

P = (50kg)(9.8m/s^2)(132m)

\boxed{P = 64,680J}

(b).

When the payload reaches the bottom of the shaft, all of its potential energy is converted into its kinetic energy; therefore,

mgh= \dfrac{1}{2}mv^2

v= \sqrt{2gh}

v = \sqrt{2*9.8*135}

\boxed{v = 51.43m/s}

(c).

The velocity in mph is

\dfrac{51.43m}{s} * \dfrac{3600s}{hr} * \dfrac{1mile}{1609.34m}

\boxed{v= 115.0mph}

5 0
3 years ago
When you exert 75 N on a jack to lift a 6000 N car, what is the jack’s actual mechanical advantage? Show your work.
professor190 [17]

Answer:

80

Explanation:

<em>the </em><em>mechanical</em><em> </em><em>advantage</em><em> </em><em>is </em><em>the </em><em>ratio </em><em>of </em><em>the </em><em>load </em><em>to </em><em>the </em><em>effort</em><em> </em><em>so </em><em>it </em><em>doesn't</em><em> </em><em>have </em><em>units.</em><em>t</em><em>o</em><em> </em><em>calculate</em><em> </em><em>it </em><em>you </em><em>use </em><em>the </em><em>formula</em>

<em>mechanical</em><em> advantage</em><em>=</em><em>load/</em><em>effort</em>

<em>in </em><em>this</em><em> case</em><em> </em><em>the </em><em>load </em><em>is </em><em>6</em><em>0</em><em>0</em><em>0</em><em>N</em><em> </em><em>and </em><em>the </em><em>effort</em><em> </em><em>is </em><em>7</em><em>5</em><em>N</em>

<em>Ma=</em><em>6</em><em>0</em><em>0</em><em>0</em><em>/</em><em>7</em><em>5</em>

<em>=</em><em>8</em><em>0</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

3 0
3 years ago
Ball B is suspended from a cord of length l attached to cart A, which can roll freely on a frictionless, horizontal track. The b
Kazeer [188]

Answer:

a.Velocity of A and Velocity of B will be opposite in direction.

b.Both velocities have the same direction.

c. The two objects will move in a direction of some angle α.  

Explanation:

When the angle gets maximum the velocities of the two objects pull each other and move in opposite direction. But when the two objects make an angle zero degree with each other their motion is in the same direction.  

7 0
3 years ago
WILL GIVE BRAINLIEST!!!
myrzilka [38]
Answer is d)  
...................    



6 0
3 years ago
Read 2 more answers
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