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Mars2501 [29]
3 years ago
5

A cannon launches a 4.0kg bowling ball with 50J of kinetic energy what is the bowling ball’s speed

Physics
2 answers:
AleksAgata [21]3 years ago
7 0

Answer:

5 m/s

Explanation:

50=1/2*4v^2

4*1/2=2

25*2=50

so...

square rood of 25 is 5

answer 5 m/s

sorry if that didn't make since

kobusy [5.1K]3 years ago
4 0

Explanation:

I will try to find the formula

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By what factor must the amplitude of a sound wave be increased in order to increase the intensity by a factor of 9?a. 9 b. 2 c.
Marta_Voda [28]

Answer:

option D

Explanation:

given,

intensity\ \alpha \ (Amplitude)^2

increase the intensity by factor of 9

    I₁ = I₀

    I₂ = 9 I₀

now,

\dfrac{I_1}{I_2}=\dfrac{A_1^2}{A_2^2}

\dfrac{I_0}{9I_0}=(\dfrac{A_1}{A_2})^2

(\dfrac{A_1}{A_2})^2=\dfrac{1}{9}

\dfrac{A_1}{A_2}=\dfrac{1}{3}

      A₂ = 3 A₁

hence, amplitude increase with the factor of 3

so, the correct answer is option D

4 0
3 years ago
Read 2 more answers
The uniform rods AB and BC weigh 24 ky and kg, respectively,and the small wheel at C is of negligible weight. If the wheel ismov
victus00 [196]

The velocity of pin B after rod AB has rotated through 90* is vb = 3.2549 m/s.

<h3>What is Potential and Kinetic energy?</h3>

Potential energy is the energy that is stored in any item or system as a result of its location or component arrangement. The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles inside a system or an item.

mass of rod, mab = 2.4kg

mass of rod, mbc = 4kg

conservation of energy

T_{1}  + V_{1} = T_{2}  + V_{2}

h_{ab}  = h_{bc}  = 0.18m

potential energy at position 1,

V1 = m_{ab} gh_{ab}  + m_{bc} gh_{bc}

V1 = 2.5 * 9.81 * 0.18 + 4 * 9.81 * 0.18

V1 = 11.30112

kinetic energy T1 at position 1 is zero

potential energy at position 2 is zero

K.E at position 2,

T_{2} = \frac{1}{2} l_{ab} w^{2}_{ab} +  \frac{1}{2} m_{bc} v^{2}_{G} +  \frac{1}{2} lw^{2}_{bc}

l_{ab} =\frac{m_{ab} l^{2}_{ab}  }{3}

= 1/3 *4 * (0.36)²

=0.10368kg m²

l =\frac{m_{bc} l^{2}_{bc}  }{12}

= 1/12 *4 * (0.6)²

=0.12kg m²

on putting the values in above equation we get,

T₂ = 1.0667vb²

0 + 11.30112 = 1.0667vb² + 0

vb = 3.2549 m/s

to learn more about Kinetic and potential energy go to - brainly.com/question/18963960

#SPJ4

5 0
1 year ago
NEED ANSWER ASAP WILL MARK BRAINLIEST
lukranit [14]
Speed=30 m/s - 1.5 m/s = 28.5 m/s forward
7 0
3 years ago
How do the frequency and amplitude affect the sound?
fenix001 [56]
The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases. ( for amplitude)

Since sound at all frequencies has the same speed in air, a change in frequency means a change in wavelength. ( for frequency)
7 0
2 years ago
Read 2 more answers
A dog runs to chase a ball. He travels 6m in 3.2 seconds. How fast is the dog running?
Artyom0805 [142]
So v=d/s so the answer is 6/3.2 so the answer is 1.87m/s
4 0
3 years ago
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