Answer:
0
Explanation:
output =transfer function H(s) ×input U(s)
here H(s)=
U(s)= for unit step function
output =H(s)×U(s)
=×
=
taking inverse laplace of output
output=t×
at t=0 putting the value of t=0 in output
output =0
Determine the specific volume of superheated water vapor at 15 Mpa and 1000C, using (a) the ideal-gas equation, and (b) the stea
1 answer:
Answer:
a)
b)
Explanation:
Given that
Pressure P = 15 MPa
Temperature = 1000 C = 1273 K
a)If assume as ideal gas
The gas constant for super heated steam R is 0.461 KJ/kg.K.
We know that ideal gas equation
P v =RT
15 x 1000 x v =0.461 x 1273
b) By using steam table
From steam table we can see that volume of super heated vapot at 15 MPa and 1273 K .
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Explanation:
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Answer:
R =
Explanation:
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