Answer:
Tmax = 2.934ksi
φ = 4.58°
Explanation:
Given.
Length = 100 ft
Maximum power = 2590 hp
Angular rotate = 1700 rpm .
Outer diameter of the shaft = 8 in. Wall thickness = 3/8 in.
Calculating angular velocity.
= 1700rev/min * 2πrad/rev * 1min/60s
= 56.67πrad/s
Convert power to ft.lb/s
2590hp = 2590 * 550
= 1424500ft.lb/s
At this point, we calculate torque.
Torque = Power/Angular Velocity
Torque = 1424500/56.67π
Torque = 8000.24lb.ft
Using the torsion formula, we'll calculate maximum stress due to the shear force acting on the body:
Tmax = ½(Tc/J)
Tmax =½ of (8001.24 * 12 * 4 )/ (π/4)(4⁴ - 3.625⁴)
Tmax = ½ * 5868.656298363693
Tmax = 2934.328149181846
Tmax = 2.934ksi
Calculating the angle twist
φ = TL/JG
φ = (8001.24 * 12 * 100 * 12 )/( (π/4)(4⁴ - 3.625⁴)(4⁴ - 3.625⁴)(11)(10^6))
φ = 0.08002 rad -- convert to degrees
φ = 4.58° --- approximated
Answer:
1) the final temperature is T2 = 876.76°C
2) the final volume is V2 = 24.14 cm³
Explanation:
We can model the gas behaviour as an ideal gas, then
P*V=n*R*T
since the gas is rapidly compressed and the thermal conductivity of a gas is low a we can assume that there is an insignificant heat transfer in that time, therefore for adiabatic conditions:
P*V^k = constant = C, k= adiabatic coefficient for air = 1.4
then the work will be
W = ∫ P dV = ∫ C*V^(-k) dV = C*[((V2^(-k+1)-V1^(-k+1)]/( -k +1) = (P2*V2 - P1*V1)/(1-k)= nR(T2-T1)/(1-k) = (P1*V1/T1)*(T2-T1)/(1-k)
W = (P1*V1/T1)*(T2-T1)/(1-k)
T2 = (1-k)W* T1/(P1*V1) +T1
replacing values (W=-450 J since it is the work done by the gas to the piston)
T2 = (1-1.4)*(-450J) *308K/(101325 Pa*650*10^-6 m³) + 308 K= 1149.76 K = 876.76°C
the final volume is
TV^(k-1)= constant
therefore
T2/T1= (V2/V1)^(1-k)
V2 = V1* (T2/T1)^(1/(1-k)) = 650 cm³ * (1149.76K/308K)^(1/(1-1.4)) = 24.14 cm³
Answer and Explanation:
Maintenance Job activity is of great importance for any firm or organization as it is the deciding factor of the firm's smooth functioning of a number of operations in the firm.
This requires the consideration of various factors prior to the maintenance activity which are as follows:
1. Planning:
Proper planning must be done in order to avoid risks and how to effectively control and mitigate risks related to the workplace, personnel, equipment, material, etc and to ensure proper maintenance of the firm and it's resources.
2. Allocation of appropriate tools and equipment:
In order to ensure proper maintenance, appropriate tools and equipment should be allocated to the workers to carry out their tasks properly and to ensure the structural safety and stability.
Some of these includes equipment for protection of personnel, safety ladders, etc.
3. Safe working environment:
Ensuring the safety of the work area by taking proper safety measures like protection against machine faults thus preventing accidents, protection against the unauthorized access and entry in the working area, taking care of power supply and proper power discharges and maintaining clean and hygienic atmosphere for the safe mobility of the material and personnel.
Answer:
The area of solar panel needed in Buffalo is 22.83 m²
The area of solar panel needed in Phoenix is 31 m²
Explanation:
<u>FOR BUFFALO</u>:
First we, calculate the the annual power requirement by dividing the energy by the time of 1 year.
Therefore,
Power Requirement = P = 6000 KWhr/(1 yr)(365 days/yr)(24 hr/day)
P = 684.93 W
Now, to calculate the area we use the formula:
Area = A = P/(Annual Insolation)(Conversion Factor)
A = 684.93 W/(200 W/m²)(0.15)
<u>A = 22.83 m²</u>
<u>FOR PHOENIX</u>:
First we, calculate the the annual power requirement by dividing the energy by the time of 1 year.
Therefore,
Power Requirement = P = 11000 KWhr/(1 yr)(365 days/yr)(24 hr/day)
P = 1255.7 W
Now, to calculate the area we use the formula:
Area = A = P/(Annual Insolation)(Conversion Factor)
A = 1255.7 W/(270 W/m²)(0.15)
<u>A = 31 m²</u>
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Answer:
Explanation:
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