A mass on a spring that has been compressed 0.1 m has a restoring force of 20 N. What is the spring constant?
1 answer:
You might be interested in
Answer:
The inventors claim is not real
a) No the the freezer cannot operate in such conditions
Explanation:
From the question we are told that
The power input is
The rate of heat transfer
The temperature of the freezer content is
The ambient temperature is
Generally the coefficient of performance of a refrigerator at idea conditions is mathematically represented as
substituting values
Generally the coefficient of performance of a refrigerator at real conditions is mathematically represented as
substituting values
Now given that the COP of an ideal refrigerator is less that that of a real refrigerator then the claims of the inventor is rejected
This is because the there are loss in the real refrigerator cycle that are suppose to reduce the COP compared to an ideal refrigerator cycle where there no loss that will reduce the COP
Let
A = the amplitude of vibration
k = the spring constant
m = the mass of the object
The displacement at time, t, is of the form
x(t) = A cos(ωt)
where
ω = the circular frequency.
The velocity is
v(t) = -ωA sin(ωt)
The maximum velocity occurs when the sin function is either 1 or -1.
Therefore
Therefore
The KE (kinetic energy) is given by
The PE (potential energy) is given by
When the KE and PE are equal, then
For the oscillating spring,
Therefore
Answer:
A = the amplitude of vibration
k = the spring constant
m = the mass of the object
The displacement at time, t, is of the form
x(t) = A cos(ωt)
where
ω = the circular frequency.
The velocity is
v(t) = -ωA sin(ωt)
The maximum velocity occurs when the sin function is either 1 or -1.
Therefore
Therefore
The KE (kinetic energy) is given by
The PE (potential energy) is given by
When the KE and PE are equal, then
For the oscillating spring,
Therefore
Answer: