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3 years ago

The apparent displacement of an object as it is viewed from two different positions is known as

1 answer:

6 0

That's called 'parallax'.

To see it happen, go outside, hold your arm straight out in front
of your face and stick your thumb up. Close one eye, and notice
where your thumb appears against the houses across the street.
Now, don't move your arm, but just close the first eye and open
the other one. You'll see your thumb jump in front of a different
house. The angle that your thumb appeared to move is its parallax.

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Psychological profiling is also known as criminal profiling. True or False?

Nikolay [14]

So my opinion that is false bc. the psychological profiling not is necessary being as criminal profiling ,the criminal mean a greater,intensive word in the way of ,,killer" ,when the ,,psychological" profile is total different way

hope helped

8 0

3 years ago

Read 2 more answers

If we decrease the amount of force applied to an object, and all other factors remain the same, the amount of work completed wil

Nat2105 [25]

A ) decrease.
B ) increase.
C ) increase, then decrease.
D ) not change.

The answer is A) decrease

Take pushing a box, for example-- You push your hardest then give out, still trying to push the box. You are doing less work than what you have started with!

( Mind marking me for branliest? ; ) )

4 0

3 years ago

"Determine the magnitude of the net force of gravity acting on the Moon during an eclipse when it is directly between Earth and

spayn [35]

Answer:

Net force = 2.3686 × 10^(20) N

Explanation:

To solve this, we have to find the force of the earth acting on the moon and the force of the sun acting on the moon and find the difference.

Now, from standards;

Mass of earth;M_e = 5.98 × 10^(24) kg

Mass of moon;M_m = 7.36 × 10^(22) kg

Mass of sun;M_s = 1.99 × 10^(30) kg

Distance between the sun and earth;d_se = 1.5 × 10^(11) m

Distance between moon and earth;d_em = 3.84 × 10^(8) m

Distance between sun and moon;d_sm = (1.5 × 10^(11)) - (3.84 × 10^(8)) = 1496.96 × 10^(8) m

Gravitational constant;G = 6.67 × 10^(-11) Nm²/kg²

Now formula for gravitational force between the earth and the moon is;

F_em = (G × M_e × M_m)/(d_em)²

Plugging in relevant values, we have;

F_em = (6.67 × 10^(-11) × 5.98 × 10^(24) × 7.36 × 10^(22))/(3.84 × 10^(8))²

F_em = 1.9909 × 10^(20) N

Similarly, formula for gravitational force between the sun and moon is;

F_sm = (G × M_s × M_m)/(d_sm)²

Plugging in relevant values, we have;

F_se = (6.67 × 10^(-11) × 1.99 × 10^(30) ×

7.36 × 10^(22))/(1496.96 × 10^(8))²

F_se = 4.3595 × 10^(20) N

Thus, net force = F_se - F_em

Net force = (4.3595 × 10^(20) N) - (1.9909 × 10^(20) N) = 2.3686 × 10^(20) N

8 0

2 years ago

How does the sun rise and set

MatroZZZ [7]

Answer:

c. earth rotates on it tilted axis and orbit around the sun at the same time

Explanation:

Earth rotation can be defined as the amount of time taken by planet earth to complete its spinning movement on its axis.

This ultimately implies that, the rotation of earth refers to the time taken by earth to rotate once on its axis. One spinning movement of the earth on its axis takes approximately 24 hours to complete with respect to the sun. Thus, this makes us to experience day and night (sun rise and sun set) due to the rotation of planet about its axis.

Hence, the sun rise and set because the earth rotates on it tilted axis and orbit around the sun at the same time

8 0

3 years ago

A star is in hydrostatic equilibrium when the outward push of pressure due to core burning is exactly in balance with the inward

viktelen [127]

Answer:

a and b

Explanation:

Hydro static equilibrium holds a star steady and balanced. Whenever a star stops burning hydrogen in its center, there must be evolutionary improvements to maintain equilibrium for the star Of example, if a star's internal pressure and temperature fall, gravity will take over and force the star to contract and heat up, restoring stability. By contrast, if a star's internal pressure and temperature rises, the extra pressure causes the star to widen and cool, restoring balance.

so, according to above explanation options a and b both are true

a) A small increase in the star's internal pressure and temperature causes the star's outer layers to expand and cool.

b) A small decrease in the star's internal pressure and temperature causes the star's outer layers to contract and heat up.

7 0

3 years ago