All categories

3 years ago

At what temperature range can mercury be found as a liquid

Physics

2 answers:

Elza [17]3 years ago

4 0

Answer:

375°

Explanation:

it is because the boiling point of mercury is 375°

juin [17]3 years ago

4 0

Mercury’s melting point (also known as freezing point) is -38.83 degrees Celsius, or -37.89 degrees Fahrenheit. Anything lower than this will cause Mercury to freeze into a solid. If heated above this, it will become liquid.
Mercury’s boiling point is 356.73 degrees Celsius, or 674.11 degrees Fahrenheit. Anything above this will cause Mercury to boil. Below this will cause the Mercury to become liquid.
So, in Celsius, the temperature that Mercury can be found as liquid is -38.83 - 356.73 degrees. Or, a total of 395.56 degrees.
In Fahrenheit, the temperature that Mercury can be found as liquid is -37.89 - 674.11 degrees. Or, a total of 712 degrees.

You might be interested in

How much energy, in Joules, is needed to raise the temperature from 25.87°C to 33.16°C in a 2.66 kg block of each of the followi

RUDIKE [14]

Answer:

(a) Silver, H = 455.67 J

(b) Iron, H = 870.67 J

Explanation:

mass of block, m = 2.66 kg = 266 g

T1 = 25.87° C

T2 = 33.16° C

ΔT = T2 - T1 = 33.16 - 25.87 = 7.29° C

(a) Specific heat of silver, c = 0.235 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.235 x 7.29 = 455.67 J

(b) Specific heat of iron, c = 0.449 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.449 x 7.29 = 870.67 J

The heat required is given by

H = m x c x ΔT

H = 266 x 0.522 x 7.29 = 1012.23 J

6 0

3 years ago

Two cars are traveling along a straight line in the same direction, the lead car at 25 m/s and the other car at 35 m/s. At the m

Phoenix [80]

Answer:

a. $t_1=12.5\ s$

b. $a_2=-13.61\ m.s^{-2}$ must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c. $t_2=2.5714\ s$ is the time taken to stop after braking

Explanation:

Given:

speed of leading car, $u_1=25\ m.s^{-1}$

speed of lagging car, $u_{2}=35\ m.s^{-1}$

distance between the cars, $\Delta s=45\ m$

deceleration of the leading car after braking, $a_1=-2\ m.s^{-2}$

Time taken by the car to stop:

$v_1=u_1+a_1.t_1$

where:

$v_1=0$ , final velocity after braking

$t_1=$ time taken

$0=25-2\times t_1$

$t_1=12.5\ s$

using the eq. of motion for the given condition:

$v_2^2=u_2^2+2.a_2.\Delta s$

where:

$v_2=$ final velocity of the chasing car after braking = 0

$a_2=$ acceleration of the chasing car after braking

$0^2=35^2+2\times a_2\times 45$

$a_2=-13.61\ m.s^{-2}$ must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

time taken by the chasing car to stop:

$v_2=u_2+a_2.t_2$

$0=35-13.61\times t_2$

$t_2=2.5714\ s$ is the time taken to stop after braking

7 0

3 years ago

Which type of exercise is weightlifting?

MatroZZZ [7]

The answer is option B "anaerobic." Weightlifting deals with stress to the muscles when lifting weights and due time the muscles will begin to adapt and get stronger. Other examples of anaerobic exercise are things like: weight training, sprinting, cycling, and jumping anything that has short exertion, and high-intensity movement is an anaerobic exercise.

Hope this helps!

Nonportrit

5 0

4 years ago

Read 2 more answers

How do I find the approximate velocity of "the object", on the graph at 5 seconds?

MakcuM [25]

First, foremost, and most critically, you must look at the graph, and critically
examine its behavior from just before until just after the 5-seconds point.

Without that ability ... since the graph is nowhere to be found ... I am hardly
in a position to assist you in the process.

7 0

4 years ago

1) if you could eliminate one item from your diet to improve your heath, what would it be?

Makovka662 [10]

Answer:

Rice

Explanation:

Because I can't control eating lots of rice

3 0

3 years ago

Read 2 more answers