Car a is heading north with a velocity of 14 m/s. car b is traveling north also, with a velocity of 19 m/s. what is the relative
2 answers:
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Answer:
The intensity of the light from the bulb would be
3.501 x W/
Explanation:
Given
The Power = 110 n W = 110 x W
the distance r = 50 mm = 50 /1000 = 0.05 m
The intensity can be obtained with the relationship below;
I = Power/area ......1
The area of the sphere would be used in this case since the bulb is spherical; A=4π
Putting it into equation 1, we have;
I = P/ 4π
I = 110 x / 4 x π x
I = 3.501 x W/
Therefore the intensity of the light from the bulb would be
3.501 x W/
Answer:
(a) 2.75 fm
(b) 2.89 fm
(c) 4.70 fm
(d) 7.12 fm
Explanation:
For a given element, the radius r of its nuclei is given by;
r = r₀
Where;
A = Atomic mass of the element
r₀ = 1.2 x 10⁻¹⁵m = 1.2fm
Now let's solve for the given elements
(a) ¹²₆C
Carbon element => This has an atomic mass number of 12
Therefore its radius is given by;
r = 1.2 x
r = 1.2 x 2.29
r = 2.75 fm
(b) ¹⁴₇N
Nitrogen element => This has an atomic mass number of 14
Therefore its radius is given by;
r = 1.2 x
r = 1.2 x 2.41
r = 2.89 fm
(c) ⁶⁰₂₇Co
Cobalt element => This has an atomic mass number of 60
Therefore its radius is given by;
r = 1.2 x
r = 1.2 x 3.92
r = 4.70 fm
(d) ²⁰⁸₈₂Pb
Lead element => This has an atomic mass number of 208
Therefore its radius is given by;
r = 1.2 x
r = 1.2 x 5.93
r = 7.12 fm