Hmm... interesting topic you're writing about here!
Well, for this essay, there must be specific criteria, correct? I'll make some suggestions, but of course you don't have to go by them if you don't like 'em. So... here they are!:
- List the physical and chemical properties of glue
- List the physical and chemical properties of liquid corn starch
- Compare and contrast the physical and chemical properties of glue with the physical and chemical properties of liquid corn starch
- You can conduct some experiments with the two substances also! You can mix the two together and see how they react with each other, and incorporate the results of the experiment into your essay.
- You can mix glue with some other liquid substances too, and incorporate your results into your essay. You can see whether each substance the glue mixes with creates a homogeneous or heterogeneous mixture, etc.
- You can mix liquid corn starch with some other liquid substances too, and incorporate your results into your essay. You can see whether each substance the liquid corn starch mixes with creates a homogeneous or heterogeneous mixture, etc.
That's all I can come up with at the moment. Maybe you'll take some of these suggestions into consideration...? Anyhow, I hope I helped somehow! :)
The reaction is
CaC₂(s) + 2H₂O (l) -----> Ca(OH)₂ (s) + C₂H₂ (g)
As we have data of gas ethyne (or acetylene), C₂H₂
We can calculate the moles of acetylene and from this we can estimate the mass of calcium carbide taken
the moles of acetylene will be calculated using ideal gas equation
PV =nRT
R = gas constant = 0.0821 Latm/molK
T = 385 K
V = volume = 550 L
P = Pressure = 1.25 atm
n = moles = ?
n = PV /RT = 1.25 X 550 / 0.0821 X 385 = 21.75 mol
As per balanced equation these moles of acetylene will be obtained from same moles of calcium carbide
moles of calcium carbide = 21.75mol
molar mass of CaC₂ = 40 + 24 = 64
mass of CaC₂ = moles X molar mass = 21.75 X 64 = 1392g
Answer:
Q = 7.0
Q = kc. The reaction is in equilibrium
Explanation:
Based on the reaction:
Br₂ + Cl₂ ⇄ 2BrCl
Equilibrium constant of the reaction, kc, is the ratio of <em>equilibrium concentrations</em> products over reactants powered to its reaction coefficient:
Kc = [BrCl]² / [Br₂] [Cl₂] = 7.0
Now, reaction quotient, Q, is write as the same Kc but the concentrations are actual concentrations:
Q = [BrCl]² / [Br₂] [Cl₂]
Replacing:
Q = [0.00415M]² / [0.00366M] [0.000672M]
Q = 7.0
Now, as Q = Kc = 7.0, the reaction mixture is in equilibrium
They eat autotrophs, or each other. That's how they get energy.
Hope that answered your question.
Explanation:
Assuming that moles of nitrogen present are 0.227 and moles of hydrogen are 0.681. And, initially there are 0.908 moles of gas particles.
This means that, for 
moles of 
+ moles of 
= 0.908 mol
Since, 2 moles of = 
= 0.454 mol
As it is known that the ideal gas equation is PV = nRT
And, as the temperature and volume were kept constant, so we can write
= 
= 
= 
= 5.2 atm
Therefore, we can conclude that the expected pressure after the reaction was completed is 5.2 atm.
