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2 years ago

Which of the following scientific terms has the most evidence and observations?

1 answer:

7 0

The correct answer should be B. a scientific law. A hypothesis is a belief by the scientist that may or may not be proven so it exists before evidence and observation, while a theory comes later. However, a law is observation itself and is always evidence of itself. There is no belief or lack of knowledge as to what will happen when it comes to laws. The law of action and reaction has plenty evidence and can easily be observed.

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The speed of a particle moving in a circle 2.0 m in radius increases at the constant rate of 4.4 m/s2. At an instant when the ma

Law Incorporation [45]

Answer:

The speed of the particle is 2.86 m/s

Explanation:

Given;

radius of the circular path, r = 2.0 m

tangential acceleration, $a_t$ = 4.4 m/s²

total magnitude of the acceleration, a = 6.0 m/s²

Total acceleration is the vector sum of tangential acceleration and radial acceleration

$a = \sqrt{a_c^2 + a_t^2}\\\\$

where;

$a_c$ is the radial acceleration

$a = \sqrt{a_c^2 + a_t^2}\\\\a^2 = a_c^2 + a_t^2\\\\a_c^2 = a^2 -a_t^2\\\\a_c = \sqrt{a^2 -a_t^2}\\\\a_c = \sqrt{6.0^2 -4.4^2}\\\\a_c = \sqrt{16.64}\\\\a_c = 4.08 \ m/s^2$

The radial acceleration relates to speed of particle in the following equations;

$a_c = \frac{v^2}{r}$

where;

v is the speed of the particle

$v^2 = a_c r\\\\v= \sqrt{a_c r} \\\\v = \sqrt{4.08 *2}\\\\v = 2.86 \ m/s$

Therefore, the speed of the particle is 2.86 m/s

6 0

3 years ago

1. In a certain semiconducting material the charge carriers each have a charge of 1.6 x 10-19 C. How many are entering the semic

Gennadij [26K]

Answer:

The number of charges is 1.25 × 10¹⁰

Explanation:

Current is the amount of charge flowing through a conductor per second. The formula for current (I) is given as:

I = Q/t

Where Q is the charge flowing in coulombs and t is the time taken in seconds.

Given that I = 2.0 nA = 2 × 10⁻⁹ A and t = 1 sec

I = Q / t

Q = It = 2 × 10⁻⁹ × 1 = 2 × 10⁻⁹ C

Since each charge = 1.6 x 10⁻¹⁹ C, therefore:

The number of charges = 2 × 10⁻⁹ C / 1.6 x 10⁻¹⁹ C = 1.25 × 10¹⁰

5 0

2 years ago

A 1,200 kg car rolls down a hill with its brakes off and transmission in neutral. At one moment it is moving 5.0 m/s. A little l

Y_Kistochka [10]

The change in kinetic energy of the car is equivalent to the change in its potential energy. Thus:
K.E = P.E
1/2 x mΔv² = mgΔh
h = (8.2² - 5²) / 2(9.81)
h = 2.15 meters

4 0

3 years ago

Arrange the movement/act/organization in ascending order of occurrence. Energy Supply and Environmental Coordination Act Nature

nadya68 [22]

Answer:

PLATO!!!!! THESE ARE RIGHT!!! OTHERS ARE NOT CORRECT. I JUST GOT IT RIGHT ON PLATO

Explanation:

1. federal water pollution control act

2.nature conservancy

3. clean air act

4. water quality act

5. endangered species preservation act

6. clean water act

7. energy supply and environmental coordination act

8. eastern wilderness act

9. toxic substance act

10. intergovernmental panel on climate change (IPCC).

5 0

2 years ago

Three boxes in contact rest side-by-side on a smooth, horizontal floor. Their masses are 5.0-kg, 3.0-kg, and 2.0-kg, with the 3.

Ivahew [28]

Answer:

(a)Look at the attached graphic

(b)

(b)-1 Equation 1 : m1= 5kg

50-F1= 5 *a

(b)-2 Equation 2 : m2= 3kg

F1-F2= 3 *a

(b)-3 Equation 3 : m3= 2kg

F2 = 2*a

(d) F2 =10 N

Explanation:

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

(a) Draw the free-body diagrams for each of the boxes

Look at the attached graphic

(b) Write Newton’s equation for each mass along the horizontal direction.

Data: m1= 5.0-kg ,m2= 3.0-kg , ,m3= 2.0-kg

Look m1 free-body diagram:

∑Fx = m1*a

50-F1= 5 *a Equation 1

Look m2 free-body diagram:

∑Fx = m2*a

F1-F2= 3 *a Equation 2

Look m3 free-body diagram:

∑Fx = m3*a

F2 = 2*a Equation 3

(c) What magnitude force does the 3.0-kg box exert on the 5.0- kg box?

Look Free body diagram of the mass set

∑Fx = m*a m= m1+m2+m3= 5+3+2 = 10 kg

50 = 10*a

a= 50/10 = 5 m/s²

We replace a = 5 m/s² in the equation 1:

50-F1= 5 *5

50-25= F1

F1 = 25 N

(d) What magnitude force does the 3.0-kg box exert on the 2.0kg box?

We replace a= 5 m/s² in the equation 3

F2 = 2*5 = 10 N

4 0

3 years ago