Answer:
The height of the building is 88.63 m.
Explanation:
Given;
initial component of vertical velocity, 
= 12 m/s sin 26° = 5.26 m/s
initial horizontal component of the velocity, 
= 12 m/s cos 26° =10.786 m/s
horizontal distance traveled by the rock, x = 40.4 m
time of flight is calculated as;
x = t
t = x /
t = 40.4 / 10.786
t = 3.75 s
Determine the final vertical velocity of the ball;
Determine the height of the rock;
Therefore, the height of the building is 88.63 m.
Answer:
17.6 m/s²
Explanation:
Given:
= 90 m/s (final velocity)
= 2 m/s (initial velocity)
Δt = 5s (change in time)
The formula for acceleration is:
= Δv / Δt
We can find Δv by doing
Δv = -
Replace the values
Δv = 90m/s - 2m/s
Δv= 88m/s
Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.
= Δv / Δt
= 
acceleration = 17.6 
Answer:
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Explanation:
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