Answer:
The frequencies that the listener at P will hear a maximum intensity are: 85.75 Hz, 171.5 Hz, 257.25 Hz and 343 Hz.
Explanation:
Path Difference Δx is given as: nλ
where λ = 
Δx can be re-written as: n×
where;
n = integer
v = speed of sound = 343 m/s
f = frequency
Δx = 19.0 m - 15.0 m
Δx = 4.0 m

f = 
f = n × 85.75 Hz
Now; n = 1, 2, 3, 4 ; the frequencies that the listener at P will hear the maximum intensity will be
when n= 1
f = 1 × 85.75 Hz
f = 85.75 Hz
when n= 2
f = 2 × 85.75 Hz
f = 171.5 Hz
when n= 3
f = 3 × 85.75 Hz
f = 257.25 Hz
when n= 4
f = 4 × 85.75 Hz
f = 343 Hz
∴ the frequencies that the listener at P will hear the maximum intensity will be : 85.75 Hz, 171.5 Hz, 257.25 Hz and 343 Hz for n =1,2,3, and 4 respectively.
The main reason for this is gravity. Gravity between objects in our solar system and milky way is strong enough to counteract this expansion. Hope it helps.
<u>Answer:</u>
The stopping car has negative acceleration.
<u>Explanation:</u>
We know acceleration is the rate of change of velocity. That is
Acceleration(a) = ( Final velocity - Initial velocity )/ Time taken.
Here Final velocity = 0 km/h( car stops) and initial velocity = 30 km/h
So acceleration = (0-30)/time = -30/ time
Time is always positive , so -30/time is negative, so the stopping car has negative acceleration.
read it carefuly you will understand why?????