Answer:
230.4 N
Explanation:
Applying,
F = kqq'/r²..................... Equation 1
Where F = Electric force, k = Coulomb's constant, q = charge in the ballon, q' = charge in the denium, r = distance between the charges.
From the question,
Given: q = -8.0×10⁻⁶ C, q' = +8.0×10⁻⁶ C, r = 0.05 m
Constant: k = 9×10⁹ Nm²/C²
Substitute these values into equation 1
F = (9×10⁹×8.0×10⁻⁶×8.0×10⁻⁶ )/0.05²
F = (576×10⁻³)/0.0025
F = 230.4 N.
Answer:
F= MASS *ACCELERATION
12=6*a
a=2 m/sec^2
v^2-u^2=2*a*s
v^2=2*2*3
v=sqrt(12)
v=3.5 m/sec
work done by force= change in kinetic energy
F*S=0.5*M*U^2-0.5*M*V^2
12*3=0 0.5*6*V^2
V=3.46 M/SEC
Explanation:
It is the speed at which a body moves without any interuptions (external forces etc)
Answer:
The speed of the football when it lift your hand is 8.86 m/s.
Explanation:
Given that,
Final speed of the football, v = 0.5 m/s
Height above the ground, s = 4 m
We need to find the speed of the football when it left your hand. The ball will move under the action of gravity. Using third equation of motion as:
So, the speed of the football when it lift your hand is 8.86 m/s. Hence, this is the required solution.
