Answer:
the final volume of the gas is = 1311.5 mL
Explanation:
Given that:
a sample gas has an initial volume of 61.5 mL
The workdone = 130.1 J
Pressure = 783 torr
The objective is to determine the final volume of the gas.
Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.
Converting the external pressure to atm ; we have
External Pressure :
The workdone W = V
The change in volume ΔV=
ΔV =
ΔV =
ΔV = 1.25 L
ΔV = 1250 mL
Recall that the initial volume = 61.5 mL
The change in volume V is
multiply through by (-), we have:
= 1250 mL + 61.5 mL
= 1311.5 mL
∴ the final volume of the gas is = 1311.5 mL
Answer:
what is it?? plss helpp taking exam rn
Explanation:
<span>3.00 grams NaHCO3 (1 mole/84.008 grams)
= 0.0357 moles of sodium bicarbonate</span>
Calcium sulfate, carbon dioxide, and water are produced when sulfuric acid and calcium carbonate interact.
<h3>What results from the reaction of calcium carbonate and sulfuric acid?</h3>
The insoluble in water free lime (CaCO3) interacts with sulfuric acid. It takes only a few minutes for sulfuric acid and lime to react and produce gypsum. H2SO4 + Lime CaCO3 = CaSO4 (gypsum).
<h3>What occurs when calcium and sulfuric acid are combined?</h3>
Each of these metals forms a layer of insoluble sulfate when exposed to sulfuric acid, which slows or stops the reaction altogether. A white precipitate of calcium sulfate and a small amount of hydrogen are formed in the calcium case.
To know more about calcium carbonate visit:-
brainly.com/question/13565765
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