Given Information:
Output power required = Pout = 2.80 MW
Efficiency = η = 30%
Intensity = I = 1180 W/m²
Required Information:
Effective area = A = ?
Answer:
Effective area = A = 7.907x10³ m²
Step-by-step explanation:
A community plans to build a facility to convert solar power into electrical power and this facility has an efficiency of 30%
As we know efficiency is given by
η = Pout/Pin
Where Pout is the output power and Pin is the input power.
Pin = Pout/η
Pin = 2.80x10⁶/0.30
Pin = 9.33x10⁶ W
The effective area of a perfectly absorbing surface used in such an installation can be found using
A = Pin/I
Where I is the in Intensity of the sunlight in W/m²
A = 9.33x10⁶/1180
A = 7.907x10³ m²
Therefore, the effective area of the absorbing surface would be 7.907x10³ m².
