Answer: 9. 9 times force
8. 7000 N/C directed towards q₂
Explanation:
9.
Let the two charges be and separated by distance r. Then the force of repulsion is given as :
where, k is the Coulomb's constant.
When the magnitude of the charges is tripled: and , the new force of repulsion, force' is:
8.
The electric field is given by:
where q is the charge and r is the distance of the point from the charge where electric field is required to be found.
It is given that,
Electric field due to charge at point a is:
Electric field due to charge at point a is:
Thus, net electric field due to both charges at a is