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solong [7]
3 years ago
12

Tell how you could distinguish between the pair of compounds by their infrared spectra: compound a ch3ch2ch2n(ch3)2 and compound

b ch3ch2ch2nh2
a. compound a will show an nh absorption while compound b will not.
b. compound b will show an nh absorption while compound a will not.
c. the infrared spectra will be the same for both compounds.
d. there is no way to differentiate between the two compounds using ir.

Chemistry
1 answer:
maksim [4K]3 years ago
6 0

Answer:-

b. compound b will show an nh absorption while compound a will not.

Explanation:-

For compound B CH3CH2CH2NH2 there are two N-H bonds present. So it will show NH absorption.

But in compound A CH3CH2CH2N(CH3)2 there are no N-H bonds. So it will not show NH absorption.

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sukhopar [10]

Answer:

Explanation:

Volume is defined as the space occupied by an object or substance irrespective of its state of matter.The conversion used from millimeter to liter is:

1 milliiliter = 0.001 L

Therefore, we can convert the volume of sample from 2.5 ml in liters as follows.

2.5 ml in liters = 2.5ml x 0.001 L/1ml

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Thus, we can conclude that the volume of given sample in liter is 0.0025 L

Hope this helps! :)

6 0
2 years ago
Use the formation reactions below such that when added together, they match the balanced equation for the combustion of methane.
muminat

Answer:

ΔH of the reaction is -802.3kJ.

Explanation:

Using Hess's law, you can know ΔH of reaction by the sum of ΔH's of half-reactions.

Using the reactions:

<em>(1) </em>Cgraphite(s)+ 2H₂(g) → CH₄(g) ΔH₁ = −74.80kJ

<em>(2) </em>Cgraphite(s)+ O₂(g) → CO₂(g) ΔH₂ = −393.5k J

<em>(3) </em>H₂(g) + 1/2 O₂(g) → H₂O(g) ΔH₃ = −241.80kJ

The sum of (2) - (1) produce:

CH₄(g) + O₂(g) → CO₂(g) + 2H₂(g) ΔH' = -393.5kJ - (-74.80kJ) = -318.7kJ

And the sum of this reaction with 2×(3) produce:

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<em>-802.3kJ</em>

7 0
3 years ago
Which expression could represent the
Elis [28]
There are a couple of ways in which you can express the concentration of a solution, and here they are: gram per liter (g/L), molarity (M), parts per million (ppm.), and percents (%). 
As you can see, only M appears in your answers, which means that the correct option should be (2) 3.5 M.
6 0
3 years ago
Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cr3+(aq) + Pb(s)2Cr2+(aq) + Pb2+(aq)
inn [45]

Answer:

3.47 ×10^-10

Explanation:

The equation of the reaction is 2Cr3+(aq) + Pb(s)------->2Cr2+(aq) + Pb2+(aq)

A total of two moles of electrons were transferred in the process. The chromium was reduced while the lead was oxidized. Hence the lead species will constitute the oxidation half equation and the chromium will constitute the reduction half equation.

E°cell = E°cathode - E°anode

E°cathode = -0.41 V

E°anode = -0.13 V

E°cell = -0.41 -(-0.13) = -0.28 V

From

E°cell = 0.0592/n log K

n= 2, K= the unknown

-0.28 = 0.0592/2 log K

log K = -0.28/0.0296

log K = -9.4595

K = Antilog ( -9.4595)

K= 3.47 ×10^-10

4 0
3 years ago
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