That statement is wrong.

Domestic violence could happen to anyone.

There are a lot of cases in which the domestic violence's victims are men or elderly people.

5 0

3 years ago

Read 2 more answers

A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectivel

faust18 [17]

Answer:

The time is 5.10 sec.

Explanation:

Given that,

Component of velocity are 30 m/s and 40 m/s.

We need to calculate the resultant velocity

Using formula of resultant velocity

$v=\sqrt{v_{x}^2+v_{y}^2}$

Put the value into the formula

$v=\sqrt{(30)^2+(40)^2}$

$v=50\ m/s$ [

We need to calculate the time

Using equation of motion

$v = u+gt$

$v = 0+gt$

$t=\dfrac{v}{g}$

Put the value into the formula

$t=\dfrac{50}{9.8}$

$t=5.10\ sec$

Hence, The time is 5.10 sec.

7 0

2 years ago

A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the high

m_a_m_a [10]

Answer:

factor that bug maximum KE change is 0.52284

Explanation:

given data

vertical distance = 6.5 cm

ripples decrease to = 4.7 cm

solution

We apply here formula for the KE of particle that executes the simple harmonic motion that is express as

KE = (0.5) × m × A² × ω² .................1

and kinetic energy is directly proportional to square of the amplitude.

$\frac{KE2}{KE1} = \frac{A2^2}{A1^2}$ .............2

$\frac{KE2}{KE1} = \frac{4.7^2}{6.5^2}$

$\frac{KE2}{KE1}$ = 0.52284

so factor that bug maximum KE change is 0.52284

5 0

3 years ago

Examine the lightbulbs in the circuit below. Write a sentence explaining what would happen if lightbulb A burned out. Repeat thi

tatiyna

If the lightbulb A in the circuit shown in the image burned out, the path for the current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.

If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.

8 0

3 years ago