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dezoksy [38]
3 years ago
13

A 350 mL sample of gas has a temperature of 30°C and a pressure of 1.20 atm. What temperature

Chemistry
1 answer:
andrew-mc [135]3 years ago
8 0

Answer:

T₂ = 180.4 K

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 350 mL

Initial pressure = 1.20 atm

Initial temperature = 30 °C (30 +273 = 303 K)

Final volume = 250 mL

Final pressure = 1 atm

Final temperature = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

T₂  =   P₂V₂ T₁ /P₁V₁

T₂ = 1 atm × 250 mL × 303 K / 1.20 atm × 350 mL

T₂ =  75750 atm .mL.  K  / 420 atm. mL

T₂ = 180.4 K

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How many coppers of each atom in the products
yarga [219]

Answer:

Explanation:

moler mass of Cu is 63.546 g/mol. Since 63.546 g of copper has 6.022 x 10 power(23) atoms (Avogadro's number). = 9.5 x 10(power)21 atoms of copper.

6 0
3 years ago
Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L
8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's  Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure  of component A is P_A and vapour pressure of component B is P_B.

P^0_A= Vapour pressure of component A in pure form

P^0_B= Vapour pressure of component B in pure form

x_A=Mole fraction of component A

x_B==Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

P_A >P^0_A\cdot x_A,P_B>P^0_B\cdot x_B

Therefore, P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B

Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.

Hence, option a,b,c and d are true.

6 0
3 years ago
Please help me out!!!
patriot [66]

Answer:

Use a scientific calculator

4 0
2 years ago
An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $7200 and his st
djyliett [7]

Answer:

22.7%

Explanation:

Given that last year stock for company A was $7200

The stock for company B last year was worth $3510

Stock in company A decreased by 24%

This means the new value of stock for company A became;

(100-24)/100 *$7200

76/100*$7200

0.76*7200 =$5472

Stock in company B decreased by 20%

This means the new value of stock for company B became;

(100-20)/100 *$3510

80/100*$3510

0.8*$3510

$2808

Original investors stock value was = $7200+$3510 =$10710

New investors stock value is = $5472+$2808=$8280

Decrease in value of stock = $10710-$8280 =$2430

percentage decrease in stock value = decrease in stock/original value of stock *100%

=2430/10710 *100 =22.689

=22.7%

7 0
3 years ago
An indicator is_____ Select all that apply.
crimeas [40]

Answer: C

Explanation:

Indicators are organic weak acids or bases with complicated structures.

5 0
2 years ago
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