Answer:
The speed of the two cars after coupling is 0.46 m/s.
Explanation:
It is given that,
Mass of car 1, m₁ = 15,000 kg
Mass of car 2, m₂ = 50,000 kg
Speed of car 1, u₁ = 2 m/s
Initial speed of car 2, u₂ = 0
Let V is the speed of the two cars after coupling. It is the case of inelastic collision. Applying the conservation of momentum as :
V = 0.46 m/s
So, the speed of the two cars after coupling is 0.46 m/s. Hence, this is the required solution.
velocity is magnitude and direction. its unit is meter per second
Answer: +2.10V
Explanation:
Using Nernst equation :
![E_{cell}=E^o_{cell}-\frac{0.059}{n}\log [Al^{3+}]^2\times [I^-]^6](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.059%7D%7Bn%7D%5Clog%20%5BAl%5E%7B3%2B%7D%5D%5E2%5Ctimes%20%5BI%5E-%5D%5E6)
where,
= standard emf for the cell = +2.20 V
n = number of electrons in oxidation-reduction reaction = 6
= emf of the cell = ?
![[Al^{3+}]](https://tex.z-dn.net/?f=%5BAl%5E%7B3%2B%7D%5D)
= concentration = 
![[I}^{-}]](https://tex.z-dn.net/?f=%5BI%7D%5E%7B-%7D%5D)
= concentration = 
Now put all the given values in the above equation, we get:
![E_{cell}=+2.20-\frac{0.059}{6}\log [5.0\times 10^{-3}]^2\times [0.10]^6](https://tex.z-dn.net/?f=E_%7Bcell%7D%3D%2B2.20-%5Cfrac%7B0.059%7D%7B6%7D%5Clog%20%5B5.0%5Ctimes%2010%5E%7B-3%7D%5D%5E2%5Ctimes%20%5B0.10%5D%5E6)
The standard emf for the cell using the overall cell reaction below is +2.10 V
Net force = 50 + 50 = 100 M
Since two forces act towards the same direction , total force should be their sum amd towards the same direction as the two forces
Velocity = distance (m) /time (s)
convert kilometers to metres (132300), substitute into formula.
convert hours to seconds (18000), substitute into formula. it becomes,
132300 divided by 18000 = 7.35 M/S
always answer questions in the units given in the question.
to get m/s into km/h, multiply by 3.6, therefore it equals 24.46 km/h
