Question

A "swing" ride at a carnival consists of chairs that are swung in a circle by 11.0 m cables attached to a vertical rotating pole, as the drawing shows. Suppose the total mass of a chair and its occupant is 283 kg.
(a) Determine the tension in the cable attached to the chair.
(b) Find the speed of the chair.

Answer 1

Answer:

a. tension of the cable attached to chair = 2.77kN

b. speed of the chair = 10.38m/s

Explanation:

A. tension of the cable is calculated by mass of the chair multiply by gravitational acceleration.

Tension(T) = m*g

where, m= 283kg

           length of cable = 11m

           and g=9.8m/s2

tension = mg = 283*9.8

            =2773.4 N = 2.77kN

b. speed of the chair = $\sqrt{\frac{tension}{mass/length}}$

$\sqrt{\frac{2773.4}{283/11}}$ = 10.38m/s