1. the max height is solved from v = square root of 2 gy where g is equal to 9.8 m/s2/ hence y is equal to 8.62 meters.

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2. time at max height is solve when velocity = 0. ( 0 = -9.81*t +13); t = 1.325 seconds

3. time required for the entire trip is 2*1.325 equal to 2.65 seconds.

4. without air resistance, the velocity just before the ball hits the ground is the same as its initial velocity, 13 m/s.</span>

**Answer:**

Force = 80422.4 N

**Explanation:**

Given that,

Initial speed, u = 0 m/s

Final speed, v = 1900 km/h = 527.78 m/s ( 1 km/h = m/s)

Time taken, t = 2.1 s

So, Applying equation of motion as:

According to the Newton's second law of motion:-

Mass = 320 kg

So,

<u>**Force = 80422.4 N**</u>

Answer:the required formula is

Kinetic energy =0.5*m*v^2

given

Kinetic energy =22 J

v=velocity =3m/s

m=mass=?

Explanation: