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kogti [31]
3 years ago
7

A pesticide was applied to a population of roaches, and it was determined that the LD50 was 55mgkg. If the average mass of a roa

ch was 0.02kg, which of the following approaches will determine the dose in mg per roach?
Physics
1 answer:
zhannawk [14.2K]3 years ago
0 0

Answer:

55mg/kg * 0.02kg which gives 1.1 mg pesticides

Explanation:

(Options are missing)

If the average mass or weight of a roach is 0.02kg

And 55mg is needed per 1 kg roaches

The amount or size of pesticide required for 0.02kg roach is 55mg/kg * 0.02kg

Size = 55mg/kg * 0.02 kg

Size = 1.1mgkg/kg

Size = 1.1 mg

So, the size of pesticide required is 1.1mg

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An object has 16N of force being applied to the right, 16N of force being applied to the left, and 4N of force being applied dow
goldenfox [79]

Answer:

4N downward

Explanation:

the 16N left and right cancel each other out, so you are left with the 4N downward.

6 0
2 years ago
An elevator starts from rest with a constant. upward acceleration andmoves 1m in the first. 1.8 s. A passenger in the elevator i
mina [271]
Newton's second law tells you: 

Sum of forces on an object = ma 

Here, the forces acting on the bundle are the tension in the string and the force of gravity, these two must combine to yield the acceleration of the bundle. 

So we have: 

T-mg = ma 

or T=m(g+a) 

We know m=8.7kg, we need to find a from the information 

starting from rest, an accelerating object covers distance according to: 

<span>dist = 1/2 at^2 </span>

to cover 1m in 1.8s, we have: 

a=2d/t^2 = 2x1/1.8^2 = 0.62 m/s/s 

Thus, the tension in the string is: 

<span>T = m(g+a)
=  8.7</span>kg(9.8m/s/s+0.62m/s/s) 
<span>
<span>T =  90.654 N
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
5 0
2 years ago
Somebody please explain how to solve this. Thanks in advance!
Jobisdone [24]

work done is product of force and displacement of point of application of force

so here we have to check the product of force and displacement both

Now we will put the least to maximum work in the following order

1. -A man exerts strenuous effort in pushing a stationary wall

2. -A flea pushes a speck of dirt 1 cm

3. -A farmer pushes a 2 kg wheelbarrow 20 m

4. -A cannon launches a 3 kg cannonball a distance of 200

5. -A 2000 kg car travels 400 m down a road

6. -Space shuttle Atlantis launches from the ground into near-Earth orbit

5 0
2 years ago
Ksp for agbr is 5x10-13. what is the maximum concentration of silver ion that you can have in a 0.1 m solution of nabr?
liberstina [14]

Answer : The maximum concentration of silver ion is 5\times 10^{-12}m

Solution : Given,

K_{sp} for AgBr = 5\times 10^{-13}

Concentration of NaBr solution = 0.1 m

The equilibrium reaction for NaBr solution is,

NaBr(aq)\rightleftharpoons Na^++Br^-

The concentration of NaBr solution is 0.1 m that means,

[Na^+]=[Br^-]=0.1m

The equilibrium reaction for AgBr is,

                          AgBr\rightleftharpoons Ag^++Br^-

At equilibrium                     s       s

The expression for solubility product constant for AgBr is,

K_{sp}=[Ag^+][Br^-]

The concentration of Ag^+ = s

The concentration of Br^- = 0.1 + s

Now put all the given values in K_{sp} expression, we get

5\times 10^{-13}=(s)(0.1+s)

By rearranging the terms, we get the value of 's'

s=5\times 10^{-12}m

Therefore, the maximum concentration of silver ion is 5\times 10^{-12}m.

4 0
3 years ago
Read 2 more answers
What is the kinetic energy of a bicycle with a mass of 16 kg traveling at a velocity of 5 m/s
fenix001 [56]

Answer:

200J

Explanation:

K.E=½mv²

K.E=½×16kg×5m/s²

K.E=8kg×25

K.E=200J

4 0
2 years ago
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