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Genrish500 [490]
4 years ago
13

After heavy rains, the floodplain of a river can deposit sediment. The newly deposited soil is nutrient rich and would be good A

. to use in a construction area. B. for growing vegetation and crops. C. for holding objects in the ground. D. to use as food for farm animals.
Physics
2 answers:
emmasim [6.3K]4 years ago
6 0
The answer is B for growing vegetation and crops. 
AURORKA [14]4 years ago
5 0
B. for growing vegetation and crops, because it says that, "The newly deposited soil nutrient rich and would be good." so it's good for the crops.
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Answer:

A. cell walls

Explanation:

Plants have cell walls but animals dont.

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4 years ago
A car of mass 800kg travels a distance of 40m at constant speed in a duration of 2.0s. The car exerts a forward force of 15kN.
Alex17521 [72]

W = F × s

W = 15kN × 40 m

W = 15.000 N × 40 m

W = 600.000 J

P = W/t

P = 600.000 J/2 s

P = 300.000 Watt

P = 300kWatt

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3 years ago
A spearfisher stands in shallow water and sees a fish a few feet in front of her. She throws her spear directly toward the posit
DENIUS [597]

Answer:

the spear will end up above the fish relative to the actual position of the fish.

Explanation:

due to refraction of light coming from the fish the fish will appear slightly above from its real position

So due to this refraction the spearfisher will throw the spear directly at the image of the fish due to which it will not reach the position of fish but it will reach the position above the fish.

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4 years ago
True or false an experiment in investigating the effects and development variable on the independent variable
Sergeu [11.5K]

true if you are refering to the desing of the experimnt as it does identify the variable

8 0
3 years ago
A 0.405 kg mass is attached to a spring with a force constant of 26.3 N/m and released from rest a distance of 3.31 cm from the
miv72 [106K]

Answer:

0.231 m/s

Explanation:

m = mass attached to the spring = 0.405 kg

k = spring constant of spring = 26.3 N/m

x₀ = initial position = 3.31 cm = 0.0331 m

x = final position = (0.5) x₀ = (0.5) (0.0331) = 0.01655 m

v₀ = initial speed = 0 m/s

v = final speed = ?

Using conservation of energy

Initial kinetic energy + initial spring energy = Final kinetic energy + final spring energy

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m v₀² + k x₀² = m v² + k x²

(0.405) (0)² + (26.3) (0.0331)² = (0.405) v² + (26.3) (0.01655)²

v = 0.231 m/s

8 0
4 years ago
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