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Genrish500 [490]
4 years ago
13

After heavy rains, the floodplain of a river can deposit sediment. The newly deposited soil is nutrient rich and would be good A

. to use in a construction area. B. for growing vegetation and crops. C. for holding objects in the ground. D. to use as food for farm animals.
Physics
2 answers:
emmasim [6.3K]4 years ago
6 0
The answer is B for growing vegetation and crops. 
AURORKA [14]4 years ago
5 0
B. for growing vegetation and crops, because it says that, "The newly deposited soil nutrient rich and would be good." so it's good for the crops.
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A car with a mass of 725 kg is moving at 32 m/s toward the east. What is the momentum of the car? A second car with a mass of 2,
Elden [556K]

Answer:

A compact car, with mass 725 kg, ... at 115 km/h toward the east. ... b. A second car, with a mass of 2175 kg, has the same momentum. What is its ... Glisens : m = 2175 kg;. D 21,32 xrolka. anknown. r = ? 110.6 mis east

Explanation:

7 0
3 years ago
1. (30 pts) Let x(t) = cos(πt/2) be a continuous-time signal,
posledela

Given that the function of the wave is f(x) = cos(π•t/2), we have;

a. The graph of the function is attached

b. 4 units of time

c. Even

d. 4.935 J/kg

e. 1.234 W/kg

<h3>How can the factors of the wave be found?</h3>

a. Please find attached the graph of the signal created with GeoGebra

b. The period of the signal, T = 2•π/(π/2) = <u>4</u>

c. The signal is <u>even</u>, given that it is symmetrical about the y-axis

d. The energy of the signal is given by the formula;

\frac{1}{2}  \cdot  \mu^{2} \cdot \omega ^{2}  \cdot \:  {a}^{2}  \times  \lambda

Which gives;

E = 0.5 × 1.571² × 1² × 4 = <u>4.935 J/kg</u>

e. The power of the wave is given by the formula;

E = 0.5 × 1.571² × 1² × 4 × 0.25 = <u>1.234 W/</u><u>kg</u>

Learn more about waves here:

brainly.com/question/14015797

8 0
2 years ago
A person on a daily diet of 2,500 calories should get no_more than <br> calories from fat each day.
ivann1987 [24]

Answer:

35%

Explanation:

3 0
3 years ago
Read 2 more answers
I was driving along at 20 m/s, trying to change a CD and not watching where I was going. When I looked up, I found myself 45 m f
cricket20 [7]

Answer:

a=4.44\frac{m}{s^2}

Explanation:

First we have to find the time required for train to travel 60 meters and impact the car, this is an uniform linear motion:

t=\frac{d}{v}\\\\t=\frac{60m}{30\frac{m}{s}}=2s

The reaction time of the driver before starting to accelerate was 0.50 seconds. So, remaining time for driver is 1.5 seconds.

Now, we have to calculate the distance traveled for the driver in this 0.5 seconds before he start to accelerate. Again, is an uniform linear motion:

d=vt\\d=20\frac{m}{s}(0.5s)=10m

The driver cover 10 meters in this 0.5 seconds. So, the remaining distance to be cover in 1.5 seconds by the driver are 35 meters. We calculate the minimum acceleration required by the car in order to cross the tracks before the train arrive, Since this is an uniformly accelerated motion, we use the following equation:

d=v_0t+\frac{1}{2}at^2\\a=\frac{2(d-v_0t)}{t^2}\\a=\frac{2(35m-20\frac{m}{s}*1.5s}{(1.5s)^2}\\a=4.44\frac{m}{s^2}

7 0
3 years ago
While in empty space, an astronaut throws a ball at a velocity of 11 m/s. What will the velocity of the ball be after it has tra
Mashutka [201]
The velocity will be 11 m/s
6 0
3 years ago
Read 2 more answers
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