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3 years ago

What factor affects sensation?

1 answer:

3 0

The sensation differs between right and left. depending on what your under, pain,stress,sickness and sometimes possible death. <span />

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How do you put 0.0015kg in scientific notation

Anna11 [10]

0.0015 kg would be 1.5*10^-2 kg in scientific notation

4 0

3 years ago

Se aplican dos fuerzas concurrentes a un objeto de 4N a la derecha y 5N a la izquierda. ¿Hacia donde se movió y con cuanta fuerz

Maksim231197 [3]

The forces move strongly towards the left by 1N

Given the following

Force towards the right = 4N

Force towards the left = 5N

Note that the force acting towards the left is negative, hence the force acting towards the left is -5N

Take the sum of force

Resultant force = -5N + 4N

Resultant force = -1N

This shows that the forces move strongly towards the left by 1N

Learn more here: brainly.com/question/24629099

3 0

3 years ago

Which elements do not usually interact with other elements?

d1i1m1o1n [39]

Noble gasses ( insert gases)

7 0

3 years ago

Read 2 more answers

An 89 kg man drops from rest on a diving board −3.1 m above the surface of the water and comes to rest 0.5 s after reaching the

OLga [1]

To solve this problem we will use the linear motion kinematic equations, for which the change of speed squared with the acceleration and the change of position. The acceleration in this case will be the same given by gravity, so our values would be given as,

$m= 89 kg\\x = 3.1 m\\t = 0.5s\\a = g = 9.8m/s^2$

Through the aforementioned formula we will have to

$v_f^2-v_i^2 = 2ax$

The particulate part of the rest, so the final speed would be

$v_f^2 = 2gx$

$v_f=\sqrt{2(9.8)(3.1)}$

$v_f = 7.79m/s$

Now from Newton's second law we know that

$F = ma$

Here,

m = mass

a = acceleration, which can also be written as a function of velocity and time, then

$F = m\frac{dv}{dt}$

Replacing we have that,

$F = (89)\frac{7.79}{0.5}$

$F = 1386.62N$

Therefore the force that the water exert on the man is 1386.62

3 0

3 years ago

A red train traveling at 72 km/hr and a green train traveling at 144 km/hr are headed toward one another along a straight level

Temka [501]

First, convert all the km/hr into m/s

You will get that
initial speed = 20 m/s
Initial speed of Green train = 40 m/s
Initial separation = 950 m
Velocity of approach = 20 - -40 = 60 m/s
relative acceleration = -4 m/s^2

v = u + at
0 = 60 - 4t

t = 15s

s = ut + 1/2 *at * t

s = 60 * 15 - 1/2 *4 * 225
s = 900 - 450

Separation when they stop = 450 m

hope this helps

5 0

3 years ago