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LekaFEV [45]
3 years ago
10

How is the mass of a liquid substance affected after it boils?

Chemistry
2 answers:
Damm [24]3 years ago
8 0
The boiling point is defined as the temperature...

The boiling point is defined as the temperature at which the vapor pressure of the liquid is equal to the ambient pressure, and bubbles of vapor form directly in the liquid. The normal boiling point is specified when the ambient pressure is 1 atm

Of course, if we reduce the ambient pressure, the boiling point will substantially be reduced, and this is the example of the principle of vacuum distillation, where an otherwise in volatile liquid is distilled under high vacuum.
const2013 [10]3 years ago
4 0

Answer:

When a mass of a liquid boils its molecules pass from liquid state to vapor state. This is done gradually, that is, before the boiling point is reached some molecules of the liquid evaporate forming a bubble and are liberated to the surrounding air, at the same time vapor molecules condensate and come back to the mass of liquid; the quantity of liquid and vapor states an equilibrium. As the temperature of liquid increase, more and more molecules evaporates, so it's more difficult to condensate them at the same velocity, so that the equilibrium is reestablished. Finally, at the boiling point the vapor is formed but no vapor is condensed.

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When one thing in a _____ circuit stops working, the whole circuit stops working.
scZoUnD [109]

Answer: When one thing in a <u>electric</u> circuit stops working, the whole circuit stops working.

Explanation:

8 0
3 years ago
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A rigid container of gas has a pressure of 1.72 atm and temperature of 21 oC. If the temperature increases to 85 oC, what is the
Vinil7 [7]

Answer:

the new pressure is 2.09 atm

Explanation:

you have to use gay lussac's law so the formula is

p1/t1 = p2/t2

and convert C to Kelvin k=C+273.15

1.72atm/294.15 = p2/358.15

solve for p2 by multiplying 358.15 on both sides

p2=2.09 atm

5 0
3 years ago
I need to find the chemical equation
Yuri [45]

Answer:

2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Explanation:

Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.

4 0
3 years ago
Calculate the amount of heat needed to boil 41.1 g of water (H2O), beginning from a temperature of 84.7 C . Be sure your answer
Levart [38]

Explanation:

We need to go through to stages to boil 41.1 g of water. We have to heat the sample of water from 84.7 °C to 100 °C (the boiling point) And then we have to provide enough heat to boil all the sample of water.

<em>a) Heating from 84.7 °C to 100 °C:</em>

This is calculated using the formula:

Q₁ = m * C * ΔT

Where Q₁ is the amount of heat, m is the mass of the sample, C is the specific heat of water and ΔT is the temperature change. We already know these values:

m = 41.1 g

C = 4.184 J/(g*°C)

ΔT = Tfinal - Tinitial = 100 °C - 84.7 °C

ΔT = 15.3 °C

Replacing these values we can get the amount of heat necessary for the first step:

Q₁ = m * C * ΔT

Q₁ = 41.1 g * 4.184 J/(g°C) * 15.3 °C

Q₁ = 2631 J

<em>b) Boiling 41.1 g of water:</em>

To find the amount of heat that we need to provide to the sample of water to completely boil it we can use this formula:

Q₂ = m * Cv

Where Cv is the latent heat of vaporization.

Cv = 2256 J/g

Q₂ = m * Cv

Q₂ = 41.1 g * 2256 J/g

Q₂ = 92721 J

<em>c) Total amount of heat:</em>

Qtotal = Q₁ + Q₂

Qtotal = 2631 J + 92721 J

Qtotal = 95352 J = 95400 J

Qtotal = 95.4 kJ

Answer: The amount of heat needed to boil the sample of water is 95.4 kJ or 95400 J.

8 0
2 years ago
Substrate: N-benzoyl-L-tyrosine ethyl ester (BTEE) 0.001M in 50% aqueous
andreev551 [17]

0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl in order to prepare a 50-fold diluted enzyme.

<h3>What is dilution?</h3>

Dilution is a process of making a solution of lower concentration from a solution of higher concentration by the addition of solvent to a given volume of the solution of higher concentration.

Dilution of solutions is done using the dilution formula in order to determine the given volume of diluent or stock solution required. The dilution formula is given below:

  • C1V1 = C2V2

where:

  • C1 = Initial concentration of enzyme
  • C2 = Final concentration of enzyme
  • V1 = Initial volume
  • V2 = Final volume

For the enzyme dilution;

C1 = 1 mg/mL

C2 = 1/50 mg/ml = 0.02 mg/ml

V= ?

V2 = 5 ml

V1 = C2V2/C1

V1 =  0.02 * 5/1 = 0.1 mL

Therefore, 0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl in order to prepare a 50-fold diluted enzyme.

Learn more about dilution at: brainly.com/question/24881505

#SPJ1

3 0
2 years ago
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