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bagirrra123 [75]
3 years ago
13

A student pushes on a 20.0 kg box with a force of 50 N at an angle of 30° below the horizontal. The box accelerates at a rate of

0.5 m/s2 across a horizontal floor. What is the value of the normal force on the box? 200 N 243 N 156 N 225 N

Physics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

225 N

Explanation:

"Below the horizontal" means he's pushing down at an angle.

Draw a free body diagram of the box.  There are three forces: normal force N pushing up, weight force mg pulling down, and the applied force F at an angle θ.

Sum of forces in the y direction:

∑F = ma

N − mg − F sin θ = 0

N = F sin θ + mg

Plug in values:

N = (50 N) (sin 30°) + (20.0 kg) (10 m/s²)

N = 225 N

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A cyclist going downhill is accelerating at 1. 2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is
mel-nik [20]

Answer:

\boxed {\boxed {\sf v_i= 4 \ m/s}}

Explanation:

We are asked to find the cyclist's initial velocity. We are given the acceleration, final velocity, and time, so we will use the following kinematic equation.

v_f= v_i + at

The cyclist is acceleration at 1.2 meters per second squared. After 10 seconds, the velocity is 16 meters per second.

  • v_f= 16 m/s
  • a= 1.2 m/s²
  • t= 10 s

Substitute the values into the formula.

16 \ m/s = v_i + (1.2 \ m/s^2)(10 \ s)

Multiply.

16 \ m/s = v_i + (1.2 \ m/s^2 * 10 \ s)

16 \ m/s = v_i + 12 \ m/s

We are solving for the initial velocity, so we must isolate the variable v_i. Subtract 12 meters per second from both sides of the equation.

16 \ m/s - 12 \ m/s = v_i + 12 \ m/s -12 \ m/s

4 \ m/s = v_i

The cyclist's initial velocity is <u>4 meters per second.</u>

6 0
3 years ago
A system had 150 kj of work done on it and its internal energy increased by 60 kj. How much energy did the system gain or lose a
mina [271]

Answer:

The system loses 90 kJ of heat

Explanation:

We can answer the question by using the 1st law of thermodynamics, which states that:

\Delta U=Q-W

where

\Delta U is the change in internal energy of the system

Q is the heat absorbed by the system (positive if absorbed, negative if released by the system)

W is the work done by the system (positive if done by the system, negative if done by the surrounding on the system)

In this problem, we have:

W=-150 kJ is the work done (negative, because it is done by the surrounding on the system)

\Delta U=+60 kJ is the increase in internal energy

Using the equation above, we can find Q, the heat absorbed/released by the system:

Q=\Delta U+W=+60 kJ+(-150 kJ)=-90 kJ

And the negative sign means that the system has lost this heat.

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3 years ago
What would the person’s mass be on the earth? Part B pls
Dafna1 [17]

Answer:

I hopes it helps

thank you

4 0
3 years ago
A woman takes her dog rover for a walk on a leash. She pulls on the leash with a force of 30.0 N at an angle of 29° above the ho
IrinaK [193]

19.8 N force is tending to lift Rover vertically off the ground.

<h3>What is horizontal and vertical component?</h3>

The horizontal velocity component (v_{x}) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component (v_{y}) describes the influence of the velocity in displacing the projectile vertically.

According to the question,

The women pulls the dog with a force of 30 N at an angle of  29° from the horizontal.

Horizontal component=  30cos(29°) = 22.2 N

Vertical component = 30sin(29°) = 19.8 N

Therefore,

The horizontal component would tend to make the dog move forward and the vertical component would tend lift it off the ground.

Hence,

19.8 N force is tending to lift Rover vertically off the ground.

Learn more about horizontal and vertical component here:

brainly.com/question/11776718

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2 years ago
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•Minimal to No Pesticide Use
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(More in website beneath)
Further Info/ Source: http://www.sustainabletable.org/249/sustainable-crop-production
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3 years ago
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