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bagirrra123 [75]
3 years ago
13

A student pushes on a 20.0 kg box with a force of 50 N at an angle of 30° below the horizontal. The box accelerates at a rate of

0.5 m/s2 across a horizontal floor. What is the value of the normal force on the box? 200 N 243 N 156 N 225 N

Physics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

225 N

Explanation:

"Below the horizontal" means he's pushing down at an angle.

Draw a free body diagram of the box.  There are three forces: normal force N pushing up, weight force mg pulling down, and the applied force F at an angle θ.

Sum of forces in the y direction:

∑F = ma

N − mg − F sin θ = 0

N = F sin θ + mg

Plug in values:

N = (50 N) (sin 30°) + (20.0 kg) (10 m/s²)

N = 225 N

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ki77a [65]

<u>Answer</u>

3.44 m/s


<u>Explanation</u>

The motion apply the equations of Newton's law of motion. The ball is acceleration is -9.8 m/s² (acceleration due to gravity. It is negative because the ball is going against gravity, so it is decelerating).

The first equation of Newton's law of motion is;

V = U + at

Where V is the final velocity, U is the initial velocity, a is acceleration and t the time taken.

V = 25 + (-9.8 × 2.2)

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3 years ago
If the potential across two parallel plates, separated by 4.0 cm, is 15.0 V, what is the electric field strength in volts per me
abruzzese [7]

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3 years ago
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Jorge wanted to know where the apples were

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Unpolarized light with an intensity of 22.4 ????ux passes through a polarizer whose transmission axis is vertically oriented. (a
irina1246 [14]

Answer:

a)      I₁ = 11.2 Lux , vertical direction , b)      I₂ = 1.44 Lux

Explanation:

a) A polarized is a system that absorbs light that is not polarized in the direction of its axis, therefore half of the non-polarized light must be absorbed

consequently the above the processed light has half of the incident intensity and the directional of the polarized

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is polarized in the vertical direction

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