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Natasha2012 [34]
3 years ago
8

A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution?

Chemistry
2 answers:
defon3 years ago
7 0

To solve this we use the equation,

 

M1V1 = M2V2

 

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

 

1.75 M x V1 = 0.100 M x 2.0 L

V1 = -.11 L


Tamiku [17]3 years ago
5 0

Answer : The volume of NH_4NO_3 stock solution is, 0.114 L

Solution :

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of NH_4NO_3 solution = 0.100 M

V_1 = volume of NH_4NO_3 solution = 2.00 L

M_2 = molarity of NH_4NO_3 stock solution = 1.75 M

V_2 = volume of NH_4NO_3 stock solution = ?

Now put all the given values in the above law, we get the volume of NH_4NO_3 stock solution.

(0.100M)\times (2.00L)=(1.75M)\times V_2

V_2=0.114L

Therefore, the volume of NH_4NO_3 stock solution is, 0.114 L

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