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Leona [35]
3 years ago
5

Can you explain what happens to resistance when voltage is increased?

Chemistry
1 answer:
Novay_Z [31]3 years ago
4 0
Resistance is directly proportional to voltage so when you increase Voltage resistance will also increase in order to keep the rate of flow of charge (current) constant

Hope this helps!
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Explanation:

Balanced forces  are opposite in direction and equal in size.

Balanced forces are  in a state of equilibrium.

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After Frank Palko was sentenced to death by the state of Connecticut, the Supreme Court ruled that
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Reasoning Why do you think
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3 years ago
The equilibrium constant, Kc, for the following reaction is 77.5 at 600 K. CO(g) Cl2(g) COCl2(g) Calculate the equilibrium conce
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Answer:

[CO] = 0.078M

[Cl2] = 0.078M

[COCl2] = 0.477M

Explanation:

Based on the reaction:

CO(g) Cl2(g) ⇄ COCl2(g)

<em>Where equilibrium constant, kc, is:</em>

kc = 77.5 = [COCl2] / [CO] [Cl2]

[] represents the equilibrium concentration of each gas. The initial concentration of each gas is:

[CO] = 0.555mol/1.00L = 0.555M

[Cl2] = 0.555M

And equilibrium concentrations are:

[CO] = 0.555M - x

[Cl2] = 0.555M - x

[COCl2] = x

<em>Where x is reaction coordinate</em>

Replacing in kc expression:

77.5 = [x] / [0.555M - x] [0.555M - x]

77.5 = x / 0.308025 - 1.11 x + x²

23.8719 - 86.025 x + 77.5 x² = x

23.8719 - 87.025 x + 77.5 x² = 0

x = 0.477M. Right answer

x = 0.646M. False answer. Produce negative concentrations

Replacing:

<h3>[CO] = 0.555M - 0.477M = 0.078M</h3><h3>[Cl2] = 0.078M</h3><h3>[COCl2] = 0.477M</h3>

And those concentrations are the equilibrium concentrations

6 0
3 years ago
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