Answer:
312.731
Explanation:
it had a long answer but im sure ur teacher wanted u to round it
hope this helps!
~goldfishareswag/brianna
:)
Explanation:
The given data is as follows.
= 9,
= ?
Z for hydrogen = 1
As we know that,
Energy (E) = 
where, h = planck's constant =
Js
c = speed of light =
m/s
= wavelength
According to Reydberg's equation, we will calculate the energy emitted by the photon as follows.
![\Delta E = -2.179 \times 10^{-18} J \times (Z)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{n^{2}_{1}}]](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20-2.179%20%5Ctimes%2010%5E%7B-18%7D%20J%20%5Ctimes%20%28Z%29%5E%7B2%7D%5B%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B1%7D%7D%5D)
or,
= ![-2.179 \times 10^{-18} J \times (Z)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{n^{2}_{1}}]](https://tex.z-dn.net/?f=-2.179%20%5Ctimes%2010%5E%7B-18%7D%20J%20%5Ctimes%20%28Z%29%5E%7B2%7D%5B%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B1%7D%7D%5D)
Putting the given values into the above equation as follows.
= ![-2.179 \times 10^{-18} J \times (Z)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{n^{2}_{1}}]](https://tex.z-dn.net/?f=-2.179%20%5Ctimes%2010%5E%7B-18%7D%20J%20%5Ctimes%20%28Z%29%5E%7B2%7D%5B%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B1%7D%7D%5D)
=
n = 2
Thus, we can conclude that the final level of the electron is 2.
They are different measurements
Answer:
4K + O2 ---> 2K2O
Explanation:
The valence of Potassium is +1
The valence of oxygen is -2
Thus, two atoms of potassium will attach with one atom of oxygen to form molecule of potassium oxide.
This can be written as
2K + O ---> K2O
However, this is not the balanced equation as oxygen exists as O2 molecule.
Thus, the balanced equation is
4K + O2 ---> 2K2O