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Serhud [2]
3 years ago
11

The hydroxide ion concentration of a saturated solution of ca(oh)2 is m. what is the solubility product constant for ca(oh)2

Chemistry
1 answer:
dalvyx [7]3 years ago
6 0
Solubility product constants are values to describe the saturation of ionic compounds with low solubility. A saturated solution is when there is a dynamic equilibrium between the solute dissolved, the dissociated ions, the undissolved and the compound. It is calculated from the product of the ion concentration in the solution. For the base, Ca(OH)2, the dissociation would  be as follows:<span>

Ca(OH)2 = Ca2+ + 2OH-

So, the expression for the solubility product constant would be as follows:

Ksp = [Ca2+] [OH-]^2

let x be the concentration of the Ca2+. So,

</span>
Ksp = [x] [2x]^2
<span>Ksp = 4x^3

You have to substitute the value of the concentration of the calcium hydroxide in the final expression which is not given in the problem statement in order to evaluate Ksp.
</span><span>
</span>
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Which ion La3+ or Lu3+ will form the more stable complex with EDTA4-
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3 years ago
You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain
Margarita [4]

Answer: 12


Explanation.


This problem was recently posted and deals with the conversion of units,so I give the same answer.


You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.


The conversion of units is easily undertaken once you build your conversion factors.


Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.


Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.

               a.1=a

Then, build your conversion factor from the definitions given:

  •    12 sleps is equal to 9 quibs.
  •    12 sleps = 9 quibs
  •    in virtue of the division property of equality, you can divide both sides by 12 sleps and get:

                                       1 = 12 sleps /  9 quibs ← conversion factor

Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:


  •    identity property: 9 quibs = 9 quibs × 1
  •    substitution property: 9 quibs = 9 quibs ×  12 sleps/  9 quibs

You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.


So, all you have to do now is the operations with the numbers:

       9 quibs = (9 ×  12 / 9) sleps = 12 sleps ← answer

3 0
3 years ago
Which scientist established the law of octaves?
Ray Of Light [21]

Answer:

John Newlands

Explanation:

he established the law of octaves

4 0
3 years ago
Read 2 more answers
Describe how you could prove that a bicycle is matter
Ainat [17]

Answer:

Explanation:

Matter is anything that has weight and occupies space.

To prove that a bicycle is a matter, we need to show that it has weight and will occupy space.

When you put the bicycle on a weighing scale, you will see the weight of the bicycle. This a proof that bicycle is a matter.

To show that the bicycle can occupy space, place the device in a tank full of water. From the tank, the bicycle will displace some water. Substances that cannot occupy space will not behave in such manner.

5 0
3 years ago
A 4.36 g sample of an unknown alkali metal hydroxide is dissolved in 100.0 ml of water. an acid-base indicator is added and the
Fofino [41]

Answer:

(a) 102.6g/mol

(b) Rubidium

Explanation:

Hello,

This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:

V_{base}=0.1L; M_{acid}=2.5M, V_{acid}=0.017L\\V_{base}M_{base}=V_{acid}M_{acid}

Solving for the molarity of base we've got:

M_{base}=\frac{M_{acid}*V_{acid}}{V_{base}}=\frac{2.50M*0.017L}{0.1L} =0.425M=0.425mol/L

Now, we can compute the moles of the base as:

n_{base}=0.425mol/L*0.1L=0.0425mol

(a) Now, one divides the provided mass over the previously computed moles to get the molecular mass of the unknown base:

\frac{4.36g}{0.0425mol} =102.6g/mol

(b) Subtracting the atomic mass of oxygen and hydrogen, the metal's atomic mass turns out into:

102.6g/mol-16g/mol-1g/mol=85.6g/mol

So, that atomic mass dovetails to the Rubidium's atomic mass.

Best regards.

8 0
3 years ago
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