The cart comes to rest from 1.3 m/s in a matter of 0.30 s, so it undergoes an acceleration <em>a</em> of
<em>a</em> = (0 - 1.3 m/s) / (0.30 s)
<em>a</em> ≈ -4.33 m/s²
This acceleration is applied by a force of -65 N, i.e. a force of 65 N that opposes the cart's motion downhill. So the cart has a mass <em>m</em> such that
-65 N = <em>m</em> (-4.33 m/s²)
<em>m</em> = 15 kg
Answer:
1.36m/s
Explanation:
We are given that
Mass of one acrobat,
Mass of another acrobat,
We have to find their velocity immediately after they grab onto each other.
The collision between two acrobat is inelastic
According to law of conservation of momentum
Substitute the values
(distance covered) divided by (time to cover the distance) is SPEED.
(straight-line distance and direction between start-point and end-point) is DISPLACEMENT.
(amount and direction of change in speed) divided by (time for the change) is ACCELERATION.
(amount and direction of change in momentum) divided by (time for the change) OR (mass) times (acceleration) is FORCE.
It is not a very intense star. For those doing odyssey ware. Hang on you're almost there.
