Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880
Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000
Lost Energy = 5880 - 3000 = 2880 J
In short, Your Answer would be 2880 Joules
Hope this helps!
Velocity = 90 km/h = 25 m/s
Drag coefficient, Cd = 2D/Density of air*Frontal area*sqr. velocity
Substituting,
Cd = (2*230)/(1.164*1.25*1.65*25^2) = 0.3066
Answer:
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Explanation:
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The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
The given parameters:
- <em>Tension on each strand of silk, T = 1.42 N</em>
- <em>Angle of inclination of each strand, θ = 75⁰</em>
The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;
where;
- W is the weight of the seashell
The weight of the seashell is calculated as;
The mass of the seashell is calculated as follows;
Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
Learn more about equilibrium forces here: brainly.com/question/8045102