Question

A 4.4 HP electric motor spins a shaft at 2329 rpm. Find: The torque load carried by the shaft is closest to: Select one: a)-27.06 ft*lb b. 19.24 ft*lb ? c)-31.17 ftlb d) 119.07 ftlb e)-9.92 ft*lb

Answer 1

Answer:

Load carried by shaft=9.92 ft-lb

Explanation:

Given:    Power P=4.4  HP

                    P=3281.08 W

Power:  Rate of change of work with respect to time is called power.

We know that P=$Torque\times speed$

     $\omega=\frac{2\pi N}{60}$ rad/sec

So that P=$\dfrac{2\pi NT}{60}$

So   3281.08=$\dfrac{2\pi \times 2329\times T}{60}$

      T=13.45 N-m         (1 N-m=0.737 ft-lb)

 So T=9.92 ft-lb.

Load carried by shaft=9.92 ft-lb