Answer:
r1 = 5*10^10 m , r2 = 6*10^12 m
v1 = 9*10^4 m/s
From conservation of energy
K1 +U1 = K2 +U2
0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2
0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2
M is mass of sun = 1.98*10^30 kg
G = 6.67*10^-11 N.m^2/kg^2
0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))
v2 = 5.35*10^4 m/s
//////Correct answer is C.///////
Answer:
The horizontally applied force = 2360 N
Explanation:
<em>Force:</em> Force can be defined as the product of mass and acceleration. the S.I unit of force is Newton (N)
Fh = Fr + ma......... Equation 1
Where Fh = horizontally applied force, Fr = friction force, m = mass of the crate, a = acceleration of the crate.
<em>Given: m = 400 kg, a = 1 m/s²</em>
Fr = 1/2 W, W = mg ⇒W = 400×9.8 = 3920 N
∴Fr = 1/2(3920), Fr = 1960 N
Substituting these values into equation 1
Fh = 1960 + 400×1
Fh = 1960 + 400
Fh = 2360 N
Therefore the horizontally applied force = 2360 N
Answer:
The height of the building is approximately 156.58 m
Explanation:
The mass of the ball dropped from rest from the building top = 0.660 kg
The time in which the ball falls, t = 5.65 seconds
The height, h, of the building is given from the following equation of motion;
h = u·t + ¹/₂·g·t²
Where;
u = The initial velocity of the ball = 0 m/s
g = The acceleration due to gravity = 9.81 m/s²
Plugging in the values, we have;
h = 0 × 5.65 + ¹/₂ × 9.81 × 5.65² ≈ 156.58 m
The height of the building, h ≈ 156.58 m.
