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beks73 [17]
3 years ago
13

A sample of the mineral calcite has a volume of 15 cm³ and a mass of 40.5 g. What is the density of the calcite?A.0.37 g/cm³B.2.

7 g/cm³C.55.5 g/cm³D.607.5 g/cm³
Physics
1 answer:
maxonik [38]3 years ago
5 0

Given data:

Volume of calcite (V) = 15 cm³,

mass of calcite (m) = 40.5 g,

find the

            density of calcite (ρ) = ?

density is defined as " it is the amount of matter of an object in a given volume". Simply it is the ratio of matter in an object to its volume. The unit of density is kg/m³ in SI system or g/cm³ in CGS system.

Mathematically,

                         density ( ρ) = mass/volume    

                                            = m/V     g/cm³

                                            = 40.5 g/15 cm³

                                            = 2.7 g/cm³

Hence, the density of calcite is <em>2.7 g/cm³ </em>  




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Answer:

14 m/s

Explanation:

We can solve the problem by using the law of conservation of energy.

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As the ball goes up, its speed decreases, so its kinetic energy decreases and converts into gravitational potential energy. When the ball reaches its maximum height, the speed has become zero, and all the kinetic energy has been converted into gravitational potential energy, given by:

U=mgh

where g = 9.8 m/s^2 is the gravitational acceleration and h = 10 m is the maximum height reached by the ball.

Since we can ignore air resistance, energy must be conserved, so the initial kinetic energy must be equal to the final potential energy of the ball, so we can write:

K=U\\\frac{1}{2}mv^2=mgh

And we can solve the equation to find v, the initial speed of the ball:

v=\sqrt{2gh}=\sqrt{2(9.8 m/s^2)(10 m)}=14 m/s


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2 years ago
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Dmitry_Shevchenko [17]
Using the law of conservation of momentum
m1u1+m2u2=m1v1+m2v2
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m2 is mass of second object
u1 and u2 are initial velocities of object 1 and 2 respectively
v1 and v2 are final velocities of object 1 and 2 respectively
Here, they are moving as a system after collision. Thus they will posses same final velocity
m1u1 +m2u2=v(m1+m2)
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Now momentum of system
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IceJOKER [234]

Answer:

M = 328.70g

Explanation:

From the given values:

V = 346 cm³

M of 1 cm³ of Polythene = 0.95g or 95/100g

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M = <u>(95×346)</u>

10

= <u>3</u><u>2</u><u>8</u><u>7</u><u>0</u>

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Answer:

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Impulse is given by the change in momentum of the body.

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When padding is there, the time interval of contact is large and thus, the force exerted by the body is small.

So, when a person falls on the tile floor, there is no compression and thus, the time of contact is very small and thus the impulsive force is very large, due to  which the body may damage.

So, when a person falls on the carpeted floor, there is a compression and thus, the time of contact is comparatively large and thus the impulsive force is small, due to  which the body may safe.

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