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beks73 [17]
4 years ago
13

A sample of the mineral calcite has a volume of 15 cm³ and a mass of 40.5 g. What is the density of the calcite?A.0.37 g/cm³B.2.

7 g/cm³C.55.5 g/cm³D.607.5 g/cm³
Physics
1 answer:
maxonik [38]4 years ago
5 0

Given data:

Volume of calcite (V) = 15 cm³,

mass of calcite (m) = 40.5 g,

find the

            density of calcite (ρ) = ?

density is defined as " it is the amount of matter of an object in a given volume". Simply it is the ratio of matter in an object to its volume. The unit of density is kg/m³ in SI system or g/cm³ in CGS system.

Mathematically,

                         density ( ρ) = mass/volume    

                                            = m/V     g/cm³

                                            = 40.5 g/15 cm³

                                            = 2.7 g/cm³

Hence, the density of calcite is <em>2.7 g/cm³ </em>  




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(b)

Using,

Ф = (ω'+ω).t/2........................... Equation 3

Where Ф = number of revolution of the centrifuge, ω' = initial angular velocity, ω = Final angular velocity.

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ω = v/r and ω' = u/r

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Ф = (u/r+v/r).t/2

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Ф = [(0/0.08)+(150/0.08)].100/2

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