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Schach [20]
3 years ago
12

The period of a wave is the reciprocal of its ______________.

Physics
1 answer:
Hunter-Best [27]3 years ago
6 0
Frequency

hope it helps !  
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Two football players with mass 75 kg and 100 kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively. if t
3241004551 [841]

<u><em>heyaaaaa</em></u>

<u><em>Momentum before Pb = momentum after Pa</em></u>

Pb = 75*6 - 100*8 = -350kgm/s = Pa = (75+100)V where V is the velocity of the combined mass of the two players after the collision.

<u><em>Velocity has magnitude (speed) and direction. V = -350/175 = -2m/s </em></u>

So the two players are moving at 2m/s in the direction the 100kg player was moving before the collision.

<em><u>I arbitrarily chose the direction of the smaller player as positive so the opposite direction (of the larger player) had to be negative. </u></em>

hope it helpssss!!!!!!

6 0
3 years ago
A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0055 m/s2 less than that at sea leve
pshichka [43]
Gs*rs^2 = gm*rm^2 
<span>rm = rs*√gs/gm </span>
<span>rm = 6370*√9.83/(9.83-0.009) = 6372.92 </span>
<span>mountain observatory is placed at an altitude worth 2920 m asl

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
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7 0
3 years ago
The magnetic field of an electromagnetic wave in a vacuum is Bz =(2.4μT)sin((1.05×107)x−ωt), where x is in m and t is in s. You
tatiyna

Answer:

Explanation:

Given

B_z=(2.4\mu T)\sin (1.05\times 10^7x-\omega t)

Em wave is in the form of

B=B_0\sin (kx-\omega t)

where \omega =frequency\ of\ oscillation

k=wave\ constant

B_0=Maximum\ value\ of\ Magnetic\ Field

Wave constant for EM wave k is

k=1.05\times 10^7 m^{-1}

Wavelength of wave \lambda =\frac{2\pi }{k}

\lambda =\frac{2\pi }{1.05\times 10^7}

\lambda =5.98\times 10^{-7} m

7 0
3 years ago
Your answer should be precise to 0.1 m/s. Use a gravitational acceleration of 10 m/s/s. At it lowest point, a pendulum is moving
saw5 [17]

Explanation:

It is given that,

Speed, v₁ = 7.7 m/s

We need to find the velocity after it has risen 1 meter above the lowest point. Let it is given by v₂. Using the conservation of energy as :

\dfrac{1}{2}mv_1^2=\dfrac{1}{2}mv_2^2+mgh

v_2^2=v_1^2-2gh

v_2^2=(7.7)^2-2\times 10\times 1

v_2=6.26\ m/s

So, the velocity after it has risen 1 meter above the lowest point is 6.26 m/s. Hence, this is the required solution.

4 0
3 years ago
Read 2 more answers
Which type of employee would most likely spend the majority of work time in a vehicle? O a Corrections Officer at a jail O a Dis
dsp73

Answer:

Paramedic

Explanation:

They will be on the move the whole time

8 0
3 years ago
Read 2 more answers
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