The period of a wave is the reciprocal of its _____________

Block A, with a mass of 4 kg, is moving with a speed of 2 m/s while Block B, with a mass of 8.4 kg, is moving in the opposite di

dybincka [34]

Answer:

The center of mass move with the velocity of -3.487 m/s.

Explanation:

Given values of block A.

Mass of block A, (M1) = 4 kg

Speed of block A, (V1) = 2 m/s

Given values of block B.

Mass of block B, (M2) = 8.4 kg

Speed of block B, (V2) = -6.1 m/s

Below is the formula to find the velocity of center of mass.

$Velocity = \frac{M1V1 + M2V2}{M1 + M2} \\$

$= \frac{4 \times 2 + 8.4 \times (-6.1) }{4 + 8.4} \\$

$= \frac{- 43.24}{12.4}\\$

$= - 3.487 m/s$

7 0

3 years ago

Three moles of an ideal gas are taken around the eyele acb shown in Fig.For this gas Co-29.2J/mol-K.Process ac is at constant pr

Scorpion4ik [409]

For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as

Wt=1945.475J

<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>

Generally, the equation for work is mathematically given as

Wt=wac+Wc+Wba

Therefore

Wac=Pa(Vc-Va)=nR(Tc-Ta)

Wac=3(8.314*192)

Wac=4788.864J

Wcb=P1v1-p2v2/v-1

Wcb-3*8.34*108/0.4

Wcb=-6734.34J

Wab=0

In conclusion,

Wt=wac+Wc+Wba

Wt=4788.864J+0+(-6734.34J)

Wt=+1945.475J

Read more about work

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8 0

2 years ago

Which learning style describes children who use the body effectively like a surgeon or a dancer?

creativ13 [48]

Answer:

A. Bodily Kinesthetic

Explanation:

3 0

3 years ago

If a sinusoidal electromagnetic wave with intensity 18 W/m2 has an electric field of amplitude E, then a 36 W/m2 wave of the sam

Neporo4naja [7]

Answer:

The correct option is D

Explanation:

From the question we are told that

The intensity of the first electromagnetic wave is $I = 18 \ W/m^2$

The amplitude of the electric field is $E_{max}_1 =A$

The intensity of the second electromagnetic wave is $I = 36 \ W/m^2$

Generally the an electromagnetic wave intensity is mathematically represented as

$I = \frac{1}{2} * \epsilon_o * c * E_{max}^2$

Looking at this equation we see that

$I \ \ \alpha \ \ E^2_{max}$

=> $\frac{I_1}{I_2} = [ \frac{ E_{max}_1}{ E_{max}_2} ] ^2$

=> $E_{max}_2 = \sqrt{\frac{x}{y} } * E_{max}_1$

=> $E_{max}_2 = \sqrt{\frac{36}{18} } * E$

=> $E_{max}_2 = \sqrt{2 } E$

5 0

3 years ago

How can the distance between the first bright band and the central band be increased in a double-slit experiment?

Strike441 [17]

Answer:

Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.

Explanation:

The distance $y$ from the central band to the first bright band is given by

$y = \dfrac{ \lambda D}{d}$

where $\lambda$ is the wavelength of light (or any particle), $D$ is the distance to the screen, and $d$ is the slit separation.

From this equation we see that, by increasing the wavelength $\lambda$ , increasing the distance from the screen $D$ , and decreasing the slit separation $d$ , we increase the distance between the first bright band and the central band.

Therefore, the 2nd choice "<em>Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.</em>" is correct.

8 0

4 years ago

The period of a wave is the reciprocal of its ______________.