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3 years ago

How do you make chocolate milk

Chemistry

2 answers:

Dennis_Churaev [7]3 years ago

8 0

Mix milk with chocolate syrup or powder.

Neko [114]3 years ago

4 0

Regular milk with melted chocolate and mix

Or buy cocoa powder and mix into regular milk

Weird question to be asking on a homework app but OK :)

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it is method used to separate particulates from a liquid by allowing in the solids to settle at the bottom of the mixture

wariber [46]

Answer:

Decantation

Explanation:

Decantation is one of the process of separating mixture containing solid and liquid. In this process, gravity plays a very important role. The solid part of the mixture is allowed to settle down. The liquid is removed and separated in another container. It is a process that helps in the purification of the liquid. The particles that are insoluble settles down and is further subject to be separated from the mixture.

5 0

2 years ago

How does the smell of food being cooked spread so fast ???

sladkih [1.3K]

Answer:

When we cook food in the kitchen, that's the region of higher concentration of the smell. By diffusion, the smell spreads to the whole room and thereby whole house, so anyone standing at a distance, can smell it.

5 0

3 years ago

Read 2 more answers

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

How many moles of ions are there in 3 moles of calcium chloride?

klemol [59]

Answer:

9 moles of ions

Explanation:

Our compound is: CaCl₂(s)

We dissociate it:

CaCl₂(aq) → Ca²⁺ (aq) + 2Cl⁻(aq)

Per 1 mol of chloride, we have 1 mol of calcium cation and 2moles of chlorides, so in total we have 3 moles of ions.

Therefore in 3 moles of chloride, we would have 9 moles of ions (3 . 3)

5 0

3 years ago

What is the percent composition by mass of hydrogen in nh4hco3

Simora [160]

<u>Answer:</u> The percent composition by mass of hydrogen in given compound is 6.33 %

<u>Explanation:</u>

We are given:

A chemical compound having chemical formula of $NH_4HCO_3$

It is made up by the combination of 1 nitrogen atom, 5 hydrogen atoms, 1 carbon atom and 3 oxygen atoms

To calculate the percentage composition by mass of hydrogen in the compound, we use the equation:

$\%\text{ composition of Hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100$

Mass of compound = $[(1\times 14)+(5\times 1)+(1\times 12)+(3\times 16)]=79g/mol$

Mass of hydrogen = $(5\times 1)=5g/mol$

Putting values in above equation, we get:

$\%\text{ composition of Hydrogen}=\frac{5g/mol}{79g/mol}\times 100=6.33\%$

Hence, the percent composition by mass of hydrogen in given compound is 6.33 %

6 0

3 years ago