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denis23 [38]
3 years ago
12

How do you make chocolate milk

Chemistry
2 answers:
Dennis_Churaev [7]3 years ago
8 0
Mix milk with chocolate syrup or powder.
Neko [114]3 years ago
4 0
Regular milk with melted chocolate and mix

Or buy cocoa powder and mix into regular milk


Weird question to be asking on a homework app but OK :)
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Which statement best describes an igneous intrusion? 
Andrew [12]
D. Magma is injected into surrounding rock forming an igneous intrusion.

Igneous intrusion forms when magma from under the surface of the earth is slowly pushed up to occupy spaces or cracks found among rocks and cools down and solidifies before it reaches the surface of the earth.
4 0
3 years ago
What is the mole fraction, x, of solute and the molality, m (or b), for an aqueous solution that is 19.0% naoh by mass?
Bond [772]
We will assume that the solvent is water. So, if we have 100 grams of the solution, 19 grams will be sodium hydroxide, while the remaining 81 grams will be water.

The molar weight of sodium hydroxide, NaOH, is 40. The molar weight of water is 18. Finding the moles of each:

NaOH:
19 / 40 = 0.475

Water:
81 / 18 = 4.5

Total moles present:
4.5 + 0.475 = 4.975 moles

The mole fraction of NaOH is:
0.475 / 4.975 = 0.0955

The mole fraction of NaOH is 0.0955
5 0
3 years ago
Which tools collect images during space exploration? Select three options.
Brut [27]

Answer:

space tools are the one ur llooking for :)

5 0
3 years ago
Read 2 more answers
The mass fractions of a mixture of gases are 15 percent nitrogen, 5 percent helium, 60 percent methane, and 20 percent ethane wi
cricket20 [7]

Answer:

See explanation

Explanation:

Number of moles of each gas is

Nitrogen = 15/28 = 0.536 kmoles

Helium = 5/4  = 1.25 kmoles

Methane = 60/16 = 3.75 kmoles

Ethane =    20/30 = 0.67 kmoles

Total number of moles =  0.536 kmoles + 1.25 kmoles + 3.75 kmoles +  0.67 kmoles = 6.206 kmoles

Mole fraction of each gas;

Nitrogen = 0.536 kmoles/6.206 kmoles = 0.086

Helium = 1.25 kmoles/6.206 kmoles = 0.201

Methane = 3.75 kmoles/6.206 kmoles =0.604

Ethane = 0.67 kmoles/6.206 kmoles =0.108

Partial pressure of each gas;

Nitrogen = 0.086 * 1200 kPa = 103.2 kPa

Helium = 0.201 * 1200 kPa = 241.2 kPa

Methane = 0.604 * 1200 kPa = 724.8 kPa

Ethane = 0.108 * 1200 kPa = 129.6 kPa

Apparent specific heat at constant pressure;

Cp = (0.15 * 1.039) + (0.05 * 5.1926) + ( 0.6 * 2.2537) + (0.2 * 1.7662)

Cp = 2.12 KJ Kg-1 K-1

Cv = Cp- Ru/M

Cv= 2.12 - 8.314/16.12 = 1.604 KJ Kg-1 K-1

8 0
2 years ago
If you were to mass the reactants before a reaction and then mass the products after the reaction what would you expect to find
TiliK225 [7]

Answer:

No change...

Explanation:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. For example, when wood burns, the mass of the soot, ashes, and gases equals the original mass of the charcoal and the oxygen when it first reacted. So the mass of the product equals the mass of the reactant.

<u> Mark as Brainliest please...</u>

7 0
3 years ago
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