Answer:
The mass percentage is 3.26 %.
Explanation:
The reaction between acetic acid and NaOH will be:
Thus one mole of acetic acid will react with one mole of NaOH.
The moles of NaOH used = molarity X volume = 0.1 X 30.10 mL = 3.010 mmol
The moles of acetic acid reacted = 3.010 mmol
The moles of acetic acid will be used to calculate the mass of acetic acid used
Mass of acetic acid used = moles X molar mass = 3.010mmol X 60
mass of acetic acid used = 180.6 mg = 0.1806 g
The mass of vinegar used = 5.54 g
The percentage of acetic acid in vinegar will be =%
The answer for this question I think is D
At 40 degrees Celsius, approximately 78 grams of potassium bromide can be dissolved.
The stars in the solar system are made of hydrogen and helium
Answer is: the compound is B₂O₃.
ω(O) = 68.94% ÷ 100%.
ω(O) = 0.6894; percentage of oxygen in the compound.
ω(X) = 31.06% ÷ 100%.
ω(X) = 0.3106; percentage of unknown element in the compound.
If we take 69.7 grams of the compound:
M(compound) = 69.7 g/mol.
n(compound) = 69.7 g ÷ 69.7 g/mol.
n(compound) = 1 mol.
n(O) = (69.7 g · 0.6894) ÷ 16 g/mol.
n(O) = 3 mol.
M(compound) = n(O) · M(O) + n(X) · M(X).
n(X) = 1 mol ⇒ M(X) = 21.7 g/mol; there is no element with this molecular weight.
n(X) = 2 mol ⇒ M(X) = 10.85 g/mol; this element is boron (B).