<span>Density is a physical
property which describes the mass of a substance per unit of volume of the
substance. It is expressed as Density = m / V and it has units like g/cm^3. To determine the diameter of the cylinder, we use the definition of density. We first calculate the volume from density as follows:
Density = mass / volume
Volume = mass / density
Volume = 310 g / 2.33 g/cm^3
Volume = 133.15 cm^3
Volume of a cylinder is equal to the product of pi, square of the radius of the base and the height. It is expressed as follows:
Volume = </span>πr^2h
We calculate for the radius, r, which is equal to one half the diameter.
r = √(Volume / πh)
r = √133.15 / π(46)
r = 0.9595 cm
Diameter = 2r = 2 (0.9595) = 1.92 cm
Answer:
33.3 kg of air
Explanation:
This is a problem of conversion unit.
Density is mass / volume
Therefore we have to calculate the volume in the room, to be multiply by density. That answer will be the mass of air.
Volume of the room → 9 ft . 11 ft . 10 ft = 990 ft³
Density is in g/L, therefore we have to convert the ft³ to dm³ (1 dm³ = 1L)
990 ft³ . 28.3 dm³ / 1ft³ = 28017 dm³ → 28017 L
This is the volume of the room, if we replace it in the density formula we can know the mass of air in g.
1.19 g/L = Mass of air / 28017 L
Mass of air = 28017 L . 1.19 g/L → 33340 g of air
Finally, let's convert the mass in g to kg → 33340 g . 1kg / 1000 g = 33.3 kg
Answer:
pathogens antigen mark me as brain list
Answer:
See Explanation
Explanation:
For SF6;
Since;
1.25 g of S corresponds to 4.44g of F
1 g of sulphur corresponds to 1 * 4.44/1.25 = 3.55
For SF4;
Since;
1.88 g of S corresponds to 4.44g of F
1 g of sulphur corresponds to 1 * 4.44/ 1.88 = 2.36
Hence;
Mass of oxygen per gram of sulphur in SF6/Mass of oxygen per gram of sulphur in SF4
=
3.55/2.36 = 1.5
Hence the law of multiple proportion is obeyed here.
The Earth's early atmosphere consisted of Carrbon Dioxide, methane, sulphur, ammonia, nitrogen and smaller amounts (aprox. 0.05%) of other gases.
