<span>32 mph
First, let's calculate the location of the particle at t=1, and t=4
t=1
s = 6*t^2 + 2*t
s = 6*1^2 + 2*1
s = 6 + 2
s = 8
t = 4
s = 6*t^2 + 2*t
s = 6*4^2 + 2*4
s = 6*16 + 8
s = 96 + 8
s = 104
So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
avg_vel = (104-8)/(4-1) = 96/3 = 32
And since the units were miles and hours, that means that the average speed of the particle over the interval [1,4] was 32 miles/hour, or 32 mph.</span>
Answer:
gamma ray-destruction of cancer cells
Ultraviolet wave-disruption of DNA
X-ray-diagnosis of illnesses through medical
Explanation: on edg
Answer:
E = 0.4 kWh
Explanation:
Given that,
The power of a bulb, P = 40 W
Time, t = 10 hours
We need to find the energy used by the bulb. Let it is equal to E. So,
So, 0.4 kWh of energy would be needed.
