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timurjin [86]
3 years ago
14

How many iron atoms are there in 2.50moles of each of the following? FeWO4 =? Atoms of Fe

Chemistry
2 answers:
oksano4ka [1.4K]3 years ago
4 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. Calculations are as follows:

 </span>2.50 mol FeWO4 ( 1 mol Fe / 1 mol FeWO4 ) ( <span>6.022 x 10^23 atoms Fe / 1 mol Fe )</span>= 1.51 x 10^24 atoms Fe
andrezito [222]3 years ago
3 0

There are 1.505 .10²⁴ iron atoms in 2.5 moles Wolframite (FeWO₄)

<h3>Further explanation </h3>

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

The empirical formula (EF) is the smallest atomic ratio of the constituent elements.

The empirical formula shows the simplest comparison of the atoms making up the molecule

Molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.

(EF)n = MF

A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) with

\large{\boxed{\bold{mole\:=\:\frac{grams}{the\:relative\:mass\:of\:elements\:or\:the relative\:mass\:of\:molecules} }}}

In the Wolframite( FeWO₄) compound there is 1 mole of Fe atom from 1 mole of FeWO₄ molecule

So if there are 2.5 moles of FeWO₄, the number of Fe moles is the same as 2.5 moles of Fe

Then the number of Fe atom particles in 2.5 mol Fe is:

2.5 x 6.02.10²³ particles  = 1.505 .10²⁴ iron atoms

<h3>Learn more </h3>

Avogadro's number

brainly.com/question/859564

carbon atoms in 1.50 g of butane

brainly.com/question/5122019

a mole and Avogadro’s number

brainly.com/question/1445383

Keywords: mole, Avogadro’s number, FeWO4, atoms, iron

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I really have no idea what to do here sorry. Help please.
horrorfan [7]

1. An ion is a charged atom. A molecule is a neutrally-charged combination of atoms.

2. A molecule is a combination of atoms. It can consist of atoms from one or more elements. For example, an oxygen molecule comprises two oxygen atoms. A compound is a substance made up of a combination of atoms of different elements. For example, water is a compound of hydrogen and oxygen.

3. An electron dot diagram is a simple way of representing the bond and electronic structure of molecules. A formula is a written representation of the types and numbers of atoms in a molecule.

4. As above...a formula denotes which atoms are in a molecule and how many. For example, H2SO4 tells us there are two hydrogen atoms, one sulfur atom and four oxygen atoms in each molecule of sulfuric acid.

5. An ionic bond is a type of chemical bond that stems from electrostatic attraction between ions with opposite charges. A covalent bond is another type of chemical bond that involves sharing of electrons between atoms in order to achieve a stable electronic structure for the molecule as a whole.

5 0
3 years ago
15 POINTS PLEASE HELP What volume of water must be added to 35mL of 2.6m KCl to reduce its concentration to 1.2m? Please explain
BartSMP [9]
First, find the volume the solution needs to be diluted to in order to have the desired molarity:
You have to use the equation M₁V₁=M₂V₂ when ever dealing with dilutions.

M₁=the starting concentration of the solution (in this case 2.6M)
V₁=the starting volume of the solution (in this case 0.035L)
M₂=the concentration we want to dilute to (in this case 1.2M)
V₂=the volume of solution needed for the dilution (not given)

Explaining the reasoning behind the above equation:
MV=moles of solute (in this case KCl) because molarity is the moles of solute per Liter of solution so by multiplying the molarity by the volume you are left with the moles of solute.  The moles of solute is a constant since by adding solvent (in this case water) the amount of solute does not change.  That means that M₁V₁=moles of solute=M₂V₂ and that relationship will always be true in any dilution.

Solving for the above equation:
V₂=M₁V₁/M₂
V₂=(2.6M×0.035L)/1.2M
V₂=0.0758 L
That means that the solution needs to be diluted to 75.8mL to have a final concentration of 1.2M.

 Second, Finding the amount of water needed to be added:
Since we know that the volume of the solution was originally 35mL and needed to be diluted to 75.8mL to reach the desired molarity, to find the amount of solvent needed to be added all you do is V₂-V₁ since the difference in the starting volume and final volume is equal to the volume of solvent added.
75.8mL-35mL=40.8mL
40.8mL of water needs to be added

I hope this helps.  Let me know if anything is unclear.
Good luck on your quiz!
5 0
3 years ago
Reading the above graph to the nearest tenth of a milliliter, what is the volume of sodium hydroxide at the equivalence point?
Vlada [557]

Answer:

The volume of sodium hydroxide at the equivalence point is:

  • <u>14.9 mL of sodium hydroxide</u>.

Explanation:

<u>The equivalence point occurs when, in this case, the HCl is completely neutralized with the solution of NaOH, how you can see this doesn't occur in the last point but occurs in the nineteenth point, where the pH is no more acid (below to 7) but is 11 approximately</u>, then you must see in the X-axis from this point and you can see the volume is almost 15, by this reason I calculate the valor of 14.9 milliliters.

7 0
3 years ago
If you start with 4.3 moles of NH3, how many moles of NANH2 can be produced
mash [69]

Explanation:

Mole ratio of NH3 to NaNH2 = 2 : 2.

Moles of NaNH2 produced

= 4.3mol * (2/2) = 4.3mol.

4 0
2 years ago
The normal boiling point of iodomethane, CH3I, is 42.43 8C, and its vapor pressure at 0.00 8C is 140. Torr. Calculate (a) the st
tigry1 [53]

Answer:

a=28600J; b=90.6 J/K; c=402 torr

Explanation:

(a) considering the data given

 Vapour pressure P1 =0  at Temperature T1 = 42.43˚C,

Vapour pressure P2 = 273.15 at Temperature T2= 315.58 K)

Using the Clausius-Clapeyron Equation

ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)

In 760/140 = ΔH/8.314 J/mol/K  × (1/315.58K -- 1/273.15K)

ΔH vap= +28.6 kJ/mol or 28600J

(b) using the Equation ΔG°=ΔH° - TΔS to solve forΔS.

Since ΔG at boiling point is zero,

ΔS =(ΔH°vap/Τb)

 ΔS = 28600 J/315.58 K

= 90.6 J/K

(c) using ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)

ln P298 K/1 atm =  28600 J/8.314 J/mol/K × (1/298.15K - 1/315.58K)

P298 K = 0.529 atm

                = 402 torr

8 0
3 years ago
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