Answer:
(a) 0.243 m3/day
(b) 96 mg/l
(c) 0.426 m3/min
Explanation:
The sludge has an average solids concentration of 4 percent and considering TSS concentration in the influent of 240 mg/L then solids in sludge will be 0.04*240= 9.6 mg/L
Considering the average flow of 0.3 m3/s then mass of sludge per day will be given by 0.3*1000*9.6*60*60*24/1000000=248.832 kg/day
To get volume, considering specific gravity given as 1.025 and taking density of water as 1000 kg/m3 then density of sludge is 1025 kg/m3
Volume is mass/density hence 248.832/1025=0.2427629268292 m3/day
Approximately, the volume of sludge is 0.243 m3/day.
(b)
Efficiency of 60 percent is equivalent to 0.6
Efficiency=(influent concentration- flow rate)/influent concentration
0.6=(240-flow rate)/240
Flow rate= 96 mg/l
(c)
Cycle time= 0.243/0.57=0.4263157894736 m3/min
Rounded off, cycle time is 0.426 m3/day
Answer:
3.99 mm
Explanation:
To treat a diffusive process in function of time and distance we need to solve 2nd Ficks Law. This a partial differential equation, with certain condition the solution looks like this:
![\frac{C_{s}-C_{x}}{C_{s}-C{o}} =erf(x/2\sqrt{D*t})](https://tex.z-dn.net/?f=%5Cfrac%7BC_%7Bs%7D-C_%7Bx%7D%7D%7BC_%7Bs%7D-C%7Bo%7D%7D%20%3Derf%28x%2F2%5Csqrt%7BD%2At%7D%29)
Where Cs is the concentration in the surface of the solid
Cx is the concentration at certain deep X
Co is the initial concentration of solute in the solid
and erf is the error function
First we need to solve the Cs-Cx/Cs-Co on the left to search the corresponding value later on a table.
![\frac{0.15}{0.35} =0.4285](https://tex.z-dn.net/?f=%5Cfrac%7B0.15%7D%7B0.35%7D%20%3D0.4285)
We look on a table and we see for erf(z)=0.4284 z=0.40
Then we solve for x
t} )[/tex]
Answer:
shaft is not transform 100% power
Explanation:
given data
current = 10 amp
voltage = 110 v
torque = 10.2 Nm
rotating speed N = 1000 rpm
solution
we get here first power that is consume by motor is express as
power = current × voltage .........1
power = 10 × 110
power = 1100 W
and power that transmit by shaft is express as
power = T × ω
power = T ×
power = 10.2 ×
power = 1068.14 W
so we can say from above both power
shaft is not transform 100% power
Answer:
Vehicle manufacturers specify various reference points on the frame, body, fender, bumper or suspension. On some applications, ride height may even be specified as a distance between two points on the vehicle's suspension, such as the distance from the frame rail to the axle or a suspension control arm.
Answer:429.8 KW
Explanation:
carbon dioxide Inlet temperature
and pressure 100 KPa
At given Temperature and presssure ![c_p_1=0.846 kJ/kg-k](https://tex.z-dn.net/?f=c_p_1%3D0.846%20kJ%2Fkg-k)
Flow rate ![\dot{m} =1.5 kg/s](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D1.5%20kg%2Fs)
Steam Outlet temperature and Pressure is
and pressure is 600 KPa
![c_p_2=1.014 kJ/kg-k](https://tex.z-dn.net/?f=c_p_2%3D1.014%20kJ%2Fkg-k)
Heat loss 50 KW
Applying Steady Flow Energy Equation
![\dot{m}\left ( h_1+\frac{v_1^2}{2}+z_1 \right )+\dot{Q}=\dot{m}\left ( h_2+\frac{v_2^2}{2}+z_2 \right )+\dot{W}](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%5Cleft%20%28%20h_1%2B%5Cfrac%7Bv_1%5E2%7D%7B2%7D%2Bz_1%20%5Cright%20%29%2B%5Cdot%7BQ%7D%3D%5Cdot%7Bm%7D%5Cleft%20%28%20h_2%2B%5Cfrac%7Bv_2%5E2%7D%7B2%7D%2Bz_2%20%5Cright%20%29%2B%5Cdot%7BW%7D)
Neglecting Kinetic and Potential Energy changes
![\dot{m}h_1+\dot{Q}=\dot{m}h_2+\dot{W}](https://tex.z-dn.net/?f=%5Cdot%7Bm%7Dh_1%2B%5Cdot%7BQ%7D%3D%5Cdot%7Bm%7Dh_2%2B%5Cdot%7BW%7D)
![\dot{W}=\dot{m}\left ( c_p_1T_1-c_p_2T_2\right )+\dot{Q}](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D%5Cdot%7Bm%7D%5Cleft%20%28%20c_p_1T_1-c_p_2T_2%5Cright%20%29%2B%5Cdot%7BQ%7D)
![\dot{W}=1.5\left ( 0.846\times 300-1.014\times 500\right )-50](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D1.5%5Cleft%20%28%200.846%5Ctimes%20300-1.014%5Ctimes%20500%5Cright%20%29-50)
![\dot{W}=429.8 KW](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D429.8%20KW)
Negative sign indicates work is being done on the system.