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melomori [17]
3 years ago
6

An object is accelerating at 2m/s^2. What is the net force if the mass is 125kg?

Physics
1 answer:
natita [175]3 years ago
3 0

Answer:

250 N

Explanation:

Newton's second law:

∑F = ma

∑F = (125 kg) (2 m/s²)

∑F = 250 N

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Explanation:

The specific heat capacity is the heat or energy required to change one unit mass of a substance of a constant volume by 1 °C. The formula is Cv = Q / (ΔT ⨉ m) .

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Ultraviolet radiation is dangerous because it has a high enough energy to damage skin cells. What is the BEST explanation of the
MrRissso [65]

The answer is shorter the wavelength, higher the frequency and higher the energy.

<u>Explanation:</u>

The sun radiates UV energy in a wide range of wavelength, which are invisible to human eyes. The shorter the wavelength, the more energetic the radiation, and the greater the potential for harm.

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3 years ago
The amplitude of the voltage across an inductor can be greater than the amplitude of the generator EMF in an AC RLC circuit. Con
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Answer:

VL=2107.6v

Explanation:

at resonance xc=xL

1/wc = wL

z=R

because sqr(R^2+(xL-xc))

^

(xL=xc)

V/R=I

90/28.9=3.1142A

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xL= wL

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VL=3.1142×676.785

VL=2107.6v

4 0
3 years ago
The radius of the thinner wire is 0.22 mm and the radius of the thick wire is 0.55 mm. There are 4.0 x 1028 mobile electrons per
Natasha_Volkova [10]

Answer:

0.2631 N/C

Explanation:

Given that:

The radius of the wire r = 0.22 mm = 0.22 × 10⁻³ m

The radius of the thick wire  r' = 0.55 mm = 0.55 × 10⁻³ m

The numbers of electrons passing through B, N = 6.0  × 10¹⁸ electrons

Electron mobility  μ =  6.0 x 10-4 (m/s)/(N/C)

= 0.0006

The number of electron flow per second is calculated as follows:

I = \frac{q}{t}

I = \frac{Ne}{t}

I = \frac{6*10^{18}(1.6*10^{-18})C}{1 \ s}

I = 0.96 \ A

The magnitude of the electric field is:

E = \frac{I}{ \mu n eA}

E = \frac{I}{ \mu n e(\pi r^2)}

E = \frac{0.96}{(0.0006 m/s N/C ) (4*10^{28})(1.6*10^{-19}C)(0.55*10^{-3}m)^2}

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8 0
3 years ago
The top of a ladder slides down a vertical wall at a rate of 0.125 m/s. at the moment when the bottom of the ladder is 5 m from
Contact [7]
Vertically (y-axis), horizontally(x-axis)

dy/dt = -0.125 m/s (-ve since y decreasing )

dx/dt = +0.3 m/s (+ve, x increases)

and, x = 5 m

length of the ladder = k (a constant)

k^2 = x^2 + y^2

differentiating it wrt t,

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0 = 2(5)(0.3) + 2(y)(-0.125)

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which means, when the bottom of the ladder is 5m from the wall, the top of the ladder is 12m from the bottom.

thus, k^2 = 5^2 + 12^2

length of the ladder, k = 13 m
5 0
3 years ago
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