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3 years ago

When a car traveling at 30 m/s hits the gas pedal, it speeds up to 65 m/s in 3.5 seconds. What is the car's

Physics

1 answer:

Dafna11 [192]3 years ago

3 0

The car gets accelerated to 10 m/s² to reach the final velocity of 65 m/s from 30 m/s in 3.5 seconds.

Answer:

Option C.

Explanation:

Acceleration is the ratio of change in velocity to the time taken to reach the final velocity. As here the initial velocity of car is given as 30 m/s and the final velocity is given as 65 m/s. So to reach this final velocity the car is taking a time of 3.5 seconds.

Thus, acceleration = change in velocity/Time

Acceleration = (65-30)/3.5 = 10 m/s²

So the car gets accelerated to 10 m/s² to reach the final velocity of 65 m/s from 30 m/s in 3.5 seconds.

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Explanation:

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l₁ = final length of metallic bar = 3.5cm

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= $\frac{F}{\frac{\pi }{4}(d^2) }}$

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Substitute 9425 N for F and 0.926 cm (9.26mm) for d₁ (d in the eqn)

σ = $\frac{9425}{\frac{\pi }{4}(9.26^2) }}$

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K = $\frac{140}{\sqrt{0.154} }$

K = $\frac{140}{0.3925}$

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K = 356.75MPa

σ = $356.75(0.05)^0^.^5$

= $356.75 ( 0.2236)$

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