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nordsb [41]
4 years ago
13

When a car traveling at 30 m/s hits the gas pedal, it speeds up to 65 m/s in 3.5 seconds. What is the car's

Physics
1 answer:
Dafna11 [192]4 years ago
3 0

The car gets accelerated to 10 m/s² to reach the final velocity of 65 m/s from 30 m/s in 3.5 seconds.

Answer:

Option C.

Explanation:

Acceleration is the ratio of change in velocity to the time taken to reach the final velocity. As here the initial velocity of car is given as 30 m/s and the final velocity is given as 65 m/s. So to reach this final velocity the car is taking a time of 3.5 seconds.

Thus, acceleration = change in velocity/Time

Acceleration = (65-30)/3.5 = 10 m/s²

So the car gets accelerated to 10 m/s² to reach the final velocity of 65 m/s from 30 m/s in 3.5 seconds.

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In addition to possibly releasing harmful chemicals in the environment, mining is considered B. The most dangerous job in the United States.
4 0
3 years ago
. Mass 1 has a momentum of 20 kg*m/s. Mass 2 has a momentum of 50 kg*m/s.
sesenic [268]

Answer:

55kgm/s

Explanation:

3 0
3 years ago
Two satellites are in circular orbits around a planet that has radius 9.00x10^6 m. One satellite has mass 53.0 kg , orbital radi
Andreas93 [3]

Answer:

The orbital speed of this second satellite is 5195.16 m/s.

Explanation:

Given that,

Orbital radius of first satellite r_{1}= 8.20\times10^{7}

Orbital radius of second satellite r_{2}=7.00\times10^{7}\ m

Mass of first satellite m_{1}=53.0\ kg

Mass of second satellite m_{2}=54.0\ kg

Orbital speed of first satellite = 4800 m/s

We need to calculate the orbital speed of this second satellite

Using formula of orbital speed

v=\sqrt{\dfrac{GM}{r}}

From this relation,

v_{1}\propto\dfrac{1}{\sqrt{r}}

Now, \dfrac{v_{1}}{v_{2}}=\sqrt{\dfrac{r_{2}}{r_{1}}}

v_{2}=v_{1}\times\sqrt{\dfrac{r_{1}}{r_{2}}}

Put the value into the formula

v_{2}=4800\times\sqrt{\dfrac{ 8.20\times10^{7}}{7.00\times10^{7}}}

v_{2}=5195.16\ m/s

Hence, The orbital speed of this second satellite is 5195.16 m/s.

4 0
3 years ago
The Shinkansen (bullet train in Japan) makes a trip from Tokyo Station to Kyoto station in 2 hours and 14 min. The distance trav
11Alexandr11 [23.1K]

Answer:

v =  57.2 m/s

Explanation:

The average velocity of the train can be defined as the total distance covered by the train divided by the time taken by the train to cover that distance. Therefore, we will use the following formula to find the average velocity of the train:

v = s/t

where,

s = distance covered = 460 km = (460 km)(1000 m/1 km) = 4.6 x 10⁵ m

t = time taken to cover the distance = 2 h 14 min

Now, we convert it into minutes:

t = (2 h)(60 min/1 h) + 14 min

t = 120 min + 14 min = (134 min)(60 s/1 min)

t = 8040 s

Therefore, the value of velocity will be:

v = (4.6 x 10⁵ m)/8040 s

<u>v =  57.2 m/s</u>

7 0
3 years ago
a central concept in quantum mechanics is that both matter and are alternate forms of the same entity and therefore both exhibit
Stels [109]

In quantum mechanics, a central concept is that both matter and <u>energy</u> are alternate forms of the same entity and therefore both exhibit dual characteristics of particles and of <u>waves</u>.

Matter can be defined as anything that has mass and is able to occupy space.

Thus, any physical object or substance that is found on Earth is typically composed of matter.

Similarly, energy is highly affected by the mass of a any physical object or substance just like matter,

Hence, both energy and matter are known to be made up of atoms and as a result of this fact, exhibit dual characteristics of particles and of waves.

A wave can be defined as a disturbance in a medium that progressively transports energy from a source location to another location without the transportation of matter.

In conclusion, this central concept makes it easier for us to better understand the behavior of tiny particles such as electrons.

Find more information: brainly.com/question/17203857

4 0
2 years ago
Read 2 more answers
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