The resultant force on the box is C) 10 Newtons to the left.
Explanation:
The figure of the problem is attached.
We see that there are two forces acting on the box along the horizontal direction:
- A force of 10 N acting to the right
- A force of 20 N acting to the left
By taking "to the right" as positive direction, we can rewrite the two forces as follows:
Where the second force is negative since it acts to the left.
Since the two forces are in line, we can find their resultant simply by calculating their algebraic sum. By doing so, we find:
And the negative sign tells us that the direction is to the left.
Therefore, the correct answer is
C) 10 Newtons to the left.
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Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :
F = 0.607 N
(b) Area of wall,
Let P is the average pressure on that area. It is given by :
P = 0.202 Pa
Hence, this is the required solution.