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3 years ago

What international body of chemists has decided the name of 6 new elements?

Chemistry

2 answers:

nekit [7.7K]3 years ago

8 0

<h2>Answer:</h2>

<u>The names were granted by IUPAC</u>

<h2>Explanation:</h2>

The International Union of Pure and Applied Chemistry (IUPAC) is an international, non-governmental organization whose purpose is to address issues in the chemical sciences. Every element that is newly discovered or synthesized in lab is checked and regulated by IUPAC and then it is named . Names that follow IUPAC rules are known as systematic names, or IUPAC names. IUPAC is also responsible for the nomenclature of elements.

Westkost [7]3 years ago

7 0

<span>International Union of Pure and Applied Chemistry</span>

Subject to confirmation by the union's members at a meeting in Geneva next August [1997], these will be the names of the six new elements: Element 104, Rutherfordium<span> (symbol Rf); Element 105, </span>Dubnium<span> (symbol Db); Element 106, </span>Seaborgium<span> (symbol Sg); Element 107, </span>Bohrium<span> (symbol Bh); Element 108, </span>Hassium<span> (symbol Hs), bol Mt).</span>

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jonny [76]

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3 years ago

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(Numerical problems) A car is running with the velocity of 72km/h. What will be it's velocity after 5s if it's acceleration is -

kodGreya [7K]

The car's velocity after 5s : 10 m/s

<h3>Further explanation</h3>

Given

velocity=v=72 km/h=20 m/s

time=t = 5 s

acceleration=a = -2 m/s²

Required

velocity after 5s

Solution

Straight motion changes with constant acceleration

$\tt v_f=v_i+at$

vf=final velocity

vi = initial velocity

Input the value :

$\tt v_f=20+(-2).5\\\\v_f=20-10\\\\v_f=10~m/s$

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Alborosie

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Tin has ten stable isotopes. The heaviest, 124Sn, makes up 5.80% of naturally occuring tin atoms. How many atoms of 124Sn are pr

matrenka [14]

The average atomic mass of Sn is 118.71 g/mol

the percentage of heaviest Sn is 5.80%

the given mass of Sn is 82g

The total moles of Sn will be = mass / atomic mass = 82/118.71=0.691

Total atoms of Sn in 82g = $6.023X10^{23}X0.691=4.16X10^{23}$