Based on the physics principle of conservation of energy, this radiation budget represents the accounting of the balance between incoming radiation, which is almost entirely solar radiation, and outgoing radiation, which is partly reflected solar radiation and partly radiation emitted from the Earth system, including the atmosphere.
To solve this problem it is necessary to apply the concepts related to the principle of superposition and constructive interference, that is to say everything that refers to an overlap of two or more equal frequency waves, which when interfering create a new pattern of waves of greater intensity (amplitude) whose cusp is the antinode.
Mathematically its definition can be given as:

Where
d = Width of the slit
Angle between the beam and the source
m = Order (any integer) which represent the number of repetition of the spectrum, at this case 1 (maximum respect the wavelength)
Since the point of the theta angle for which the diffraction becomes maximum will be when it is worth one then we have to:


Applying the given relation of frequency, speed and wavelength then we will have that the frequency would be:

Here the velocity is equal to the speed of light and the wavelength to the value previously found.


Therefore the smallest microwave frequency for which only the central maximum occurs is 1.5Ghz
Answer:
Solution given:
No of waves[N] =20crests & 20 troughs
=20waves
Time[T]=4seconds
distance[d]=3cm=0.03m
Now
<u>Wave</u><u> </u><u>length</u><u>=</u>3cm=3 × 
<u>Frequency</u>=
=
=5Hertz
and
Wave speed:wave length×frequency=3 ×
×5=1.5 ×
.
To solve this problem it is necessary to apply the concewptos related to Torque, kinetic movement and Newton's second Law.
By definition Newton's second law is described as
F= ma
Where,
m= mass
a = Acceleration
Part A) According to the information (and as can be seen in the attached graph) a sum of forces is carried out in mass B, it is obtained that,


In the case of mass A,


Making summation of Torques in the Pulley we have to



Replacing the values previously found,





Replacing with our values


PART B) Ignoring the moment of inertia the acceleration would be given by



Therefore the error would be,


