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Romashka-Z-Leto [24]
3 years ago
14

Structures on a bird feather act like a diffraction grating having 8000 8000 lines per centimeter. What is the angle of the firs

t-order maximum for 452 nm 452 nm light shone through a feather?
Physics
1 answer:
sammy [17]3 years ago
6 0

Answer:

Angle of first order maximum, \theta=21.19^{\circ}

Explanation:

Given that,

Wavelength of the light, \lambda=452\ nm=452\times 10^{-9}\ m

Number of lines, N = 8000 per cm

The relation between the number of lines and the slit width is given by :

d=\dfrac{1}{N}

d=\dfrac{1}{8000/cm}  

d=0.000125\ cm=1.25\times 10^{-6}\ m

The equation of grating is given by :

d\ sin\theta=n\lambda

n = 1

sin\theta=\dfrac{\lambda}{d}

sin\theta=\dfrac{452\times 10^{-9}}{1.25\times 10^{-6}}

\theta=21.19^{\circ}

So, the angle of the first-order maximum is 21.19 degrees. Hence, this is the required solution.

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Explanation:

To obtain the forces between the particles, we can use Coulomb's Law in scalar form, this is, the force between the particles will be:

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where k is Coulomb's constant, q_1 and q_2 are the charges and d is the distance between the charges.

Working a little the equation, we can take:

d^2 = k \frac{q_1 q_2}{F}

d = \sqrt{ k \frac{q_1 q_2}{F}}

And this equation will give us the distance between the charges. Taking the values of the problem

k= 9.00 \ 10^9 \frac{N \ m^2}{C^2} \\q_1 = 165.0 \mu C \\q_2 = 115.0 C\\F=- 6.00

(the force has a minus sign, as its attractive)

d = \sqrt{ 9.00 \ 10^9 \frac{N \ m^2}{C^2} \frac{(165.0 \mu C) (115.0 C)}{- 6.00 \ N}}

d = \sqrt{ 9.00 \ 10^9 \frac{N \ m^2}{C^2} \frac{(165.0 \mu C) (115.0 C)}{- 6.00 \ N}}

d = \sqrt{ 28,462,500 \ m^2}}

d = 5,335.026 m

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