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sertanlavr [38]
4 years ago
9

A record turntable is rotating at 33 1/3 rev/min. A watermelon seed is on the turntable 6.1 cm from the axis of rotation. (a) Ca

lculate the acceleration of the seed, assuming that it does not slip. .7432 Correct: Your answer is correct. m/s2 (b) What is the minimum value of the coefficient of static friction between the seed and the turntable if the seed is not to slip? .0758 Correct: Your answer is correct. (c) Suppose that the turntable achieves its angular speed by starting from rest and undergoing a constant angular acceleration for 0.20 s. Calculate the minimum coefficient of static friction required for the seed not to slip during the acceleration period.
Physics
1 answer:
Yanka [14]4 years ago
3 0

Answer:

0.37163\ m/s^2

0.07576

0.13235

Explanation:

\omega = Angular speed = \dfrac{100}{3}\times \dfrac{2\pi}{60}

r = Distance from the center = 6.1 cm

g = Acceleration due to gravity = 9.81 m/s²

Acceleration of the seed would be

a_c=r\omega^2\\\Rightarrow a_c=0.061\times (\dfrac{100}{3}\times \dfrac{2\pi}{60})^2\\\Rightarrow a_c=0.74326\ m/s^2

The acceleration of the seed is 0.74326\ m/s^2

Frictional force is given by

f=\mu mg\\\Rightarrow ma_c=\mu mg\\\Rightarrow \mu=\dfrac{a_c}{g}\\\Rightarrow \mu=\dfrac{0.74326}{9.81}\\\Rightarrow \mu=0.07576

The coefficient of friction is 0.07576

Transverse acceleration is given by

a_t=r\dfrac{\omega}{t}

The resultant acceleration is given by

a=\sqrt{a_c^2+a_t^2}\\\Rightarrow a=\sqrt{0.74326^2+(0.061\times \dfrac{100}{3}\times \dfrac{2\pi}{60}\times \dfrac{1}{0.2})^2}\\\Rightarrow a=1.29842\ m/s^2

\mu=\dfrac{1.29842}{9.81}\\\Rightarrow \mu=0.13235

The coefficient of friction is 0.13235

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3 years ago
Light from distant galaxies most likely shows a ...red shift, indicating that the universe is expandingblue shift, indicating th
ELEN [110]

Answer:

red shift, indicating that the universe is expanding

Explanation:

Doppler effect occurs when a source of a wave (e.g. light, or sound waves) moves relative to an observer; as a result of this relative motion, the wavelength of the wave appears lengthened/shortened to the observer. Two situations can occur:

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5 0
4 years ago
In a laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 2.2 rev/
Hunter-Best [27]

Answer:

n_{T} = 31.68\,rev

Explanation:

The angular acceleration is:

\ddot n_{1} = \frac{2.2\,\frac{rev}{s} -0\,\frac{rev}{s} }{8.8\,s}

\ddot n_{1} = 0.25\,\frac{rev}{s^{2}}

And the angular deceleration is:

\ddot n_{2} = \frac{0\,\frac{rev}{s}-2.2\,\frac{rev}{s} }{20\,s}

\ddot n_{2} = -0.11\,\frac{rev}{s^{2}}

The total number of revolutions is:

n_{T} = n_{1} + n_{2}

n_{T} = \frac{\left(2.2\,\frac{rev}{s} \right)^{2}-\left(0\,\frac{rev}{s} \right)^{2}}{2\cdot \left(0.25\,\frac{rev}{s^{2}} \right)} + \frac{\left(0\,\frac{rev}{s} \right)^{2}-\left(2.2\,\frac{rev}{s} \right)^{2}}{2\cdot \left(-0.11\,\frac{rev}{s^{2}} \right)}

n_{T} = 31.68\,rev

4 0
4 years ago
Hello people ~
Pepsi [2]

Answer:

Potential

Explanation:

The most accurate term is Electrostatic potential energy

  • It is denoted as UC

It's named like this because the force between charges or electrons is called electrostatic force .

5 0
3 years ago
A disk with a uniform positive surface charge density lies in the x-y plane, centered on the origin. The disk contains 2.5 x 10-
allochka39001 [22]

Answer:

E=3 x 10^4 N/c

Explanation:

The electric field strength can be found out disk with a uniform positive surface charge density by

E= (\sigma/\2epsilon_o)(1-z/ \sqrt(z^2+r^2))

σ= charge density

r= radius of the disk

z= position in which we have to find electric field = 15 cm

ε_0= constant ( vacuum permitivity)

putting values we get

E= \frac{2.5\times10^{-6}}{2\times2.5\times10^{-6}}(1-\frac{0.15}{\sqrt{0.15^2+0.075^2} })

solving we get

E=30000 N/c

E=3 x 10^4 N/c

6 0
3 years ago
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