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3 years ago

7

The answer because it is hard

2 answers:

notka56 [123]3 years ago

6 0

Follow me answer= -77

kozerog [31]3 years ago

5 0

You would get -77 as your answer

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Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24$

7 0

3 years ago

Given the function, g(x)=5x^5/x^3-2x+1, choose the correct horizontal asymptote. none y = 0 y = 1 y = 3

viktelen [127]

Answer: NONE

<u>Step-by-step explanation:</u>

Consider that m is the degree of the numerator and n is the degree of the denominator.

The rules for horizontal asymptote (H.A.) are as follows:

If m > n then no H.A. (use long division to find the slant asymptote)

If m = n then H.A. is y = leading coefficient of numerator/leading coefficient of denominator

If m < n then H.A. is y = 0

Given: g(x) = 5x⁵/(x³ - 2x + 1)

--> m = 5, n = 3

Since m > n then there is no H.A.

8 0

3 years ago

If 3t-7=5t, then 6t=?<br><br> Explain how you got your answer!

kirill [66]

Answer:

6t = -21

Step-by-step explanation:

3t-7 = 5t simplifies by subtracting 5t on both sides, then adding 7 on both sides:

3t -5t -7 +7 = 5t-5t+7

-2t = 7

t = -7/2

Then 6t = 6*-7/2 = -21

6 0

3 years ago

Read 2 more answers

The smallest square number which can be divisible by 11 and 5

Elena L [17]

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

LCM of 11 and 5=55

therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

$\sqrt{55x} = \sqrt{5 \times 11 \times x}$

the smallest value of x to make 55x a perfect square is....

$x = 11 \times 5 = 55$

Therefore the number is.... .

$55x = 55(55) = 3025$

<em>sweet</em><em> </em><em>right</em>

<h2><u>B</u><u>R</u><u>A</u><u>I</u><u>N</u><u>L</u><u>I</u><u>E</u><u>S</u><u>T</u><u> </u><u>P</u><u>L</u><u>S</u><u>.</u><u>.</u><u>.</u><u>.</u></h2>

6 0

3 years ago

Each car on a train has 200 seats how many seats are on a train with 8 cars

Sati [7]

Well it would be 200 × 8 which would equal to 1600

8 0

3 years ago

Read 2 more answers