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Firdavs [7]
4 years ago
10

A standing wave is created on a string of length 1.2 m. If the speed of the wave on the string is 60.0 m/s, what is the fundamen

tal frequency?
Physics
2 answers:
coldgirl [10]4 years ago
6 0

Answer:

Fundamental frequency in the string will be 25 Hz

Explanation:

We have given length of the string L = 1.2 m

Speed of the wave on the string v = 60 m/sec

We have to find the fundamental frequency

Fundamental frequency in the string is equal to f=\frac{v}{2L}, here v is velocity on the string and L is the length of the string

So frequency will be equal to f=\frac{v}{2L}=\frac{60}{2\times 1.2}=25Hz

So fundamental frequency will be 25 Hz

Shalnov [3]4 years ago
3 0

Answer:

25 Hz

Explanation:

Length, L = 1.2 m

velocity, v = 60 m/s

The frequency of the fundamental is given by

f = v / 2L

f = 60 / ( 2 x 1.2)

f = 25 Hz

Thus, the fundamental frequency is 25 Hz.

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While a guitar string is vibrating, you gently touch the midpoint of the string to ensure that the string does not vibrate at th
fiasKO [112]

Answer:

Option A is correct - While a guitar string is vibrating, you gently touch the midpoint of the string to ensure that the string does not vibrate at that point. The lowest-frequency standing wave that could be present on the string vibrates at twice the fundamental frequency.

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Before touching the midpoint of the string, the string vibrates with one loop.

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Option A is correct - While a guitar string is vibrating, you gently touch the midpoint of the string to ensure that the string does not vibrate at that point. The lowest-frequency standing wave that could be present on the string vibrates at twice the fundamental frequency.

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3 years ago
which best describes what happens with the sonar to sound pulses from a ship after they hit the ocean floor?
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