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IrinaK [193]
3 years ago
9

According the inverse square law, doubling the distance from the source of the sound, a speaker, for example, will drop the soun

d 6 db each time. If you were standing in the back of an auditorium, 32 feet away from a speaker not using any amplification, would you be able to hear a speaker clearly? Why or why not?
Chemistry
2 answers:
photoshop1234 [79]3 years ago
7 0

Answer:

Explanation:

D) No; 60db is normal speech. In a auditorium any other noise might mask the speaker since you are only hearing 56db.

Shtirlitz [24]3 years ago
4 0

Answer:

Yes, I would be able to hear the speaker clearly because the supposedly dropping off of sound as the distance gets farther is counteracted by "reverberations" inside the auditorium.

Explanation:

According to the "Inverse Square Law," if the distance from the sound source is doubled, the intensity of the sound will diminish by 6 decibels. This is true if the situation is in a <em>"free field,"</em> which means the sound has no reflection.

However, this is not the case in an "auditorium." An auditorium causes the <u>"reverberation" of sound. </u>This prolongs the resonance of the sound.  So, this means that even if the sound drops off by a factor of 100 (20 decibels), due to reverberations, the height of the ceiling, the kind of wall and materials used in making the seats also affect the intensity of the sound waves. This is the reason why auditoriums are used as venues for <em>concerts, presentations and the like</em> where a <u>large group of people serve as the audienc</u>e.

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The iron core, copper wire, and an electricity source.

Explanation: Me

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What must occur in order for a chemical reaction to be specifically classified as endothermic instead of exothermic?
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Answer:  B- Chemical bonds are formed. Energy is released in the form of heat.

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Read 2 more answers
What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
A sample of oxygen gas has a volume of 3.24 L at 29°C. What volume will it occupy at 104°C if the pressure and number of mol are
ohaa [14]

<u>Answer:</u> The final volume of the oxygen gas is 4.04 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.24L\\T_1=29^oC=(29+273)K=302K\\V_2=?\\T_2=104^oC=(104+273)K=377K

Putting values in above equation, we get:

\frac{3.24L}{302K}=\frac{V_2}{377K}\\\\V_2=4.04L

Hence, the final volume of the oxygen gas is 4.04 L

8 0
4 years ago
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