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SOVA2 [1]
3 years ago
9

How many valence electrons are in an atom of strontium (Sr)? Consult the periodic table. A. 5 B. 2 C. 47.90 D. 22

Chemistry
2 answers:
Eduardwww [97]3 years ago
6 0
<h2>Answer:</h2>

The option B is correct.

Strontium has 2 valence electrons.

<h3>Explanation:</h3>
  • Since strontium (Sr) is in Group 2 it will have 2 valence electrons.
Kaylis [27]3 years ago
5 0

The smallest and the basic particle of a chemical element is said to be an atom. It is made up of three subatomic particles that is electrons, protons and neutrons.  The neutrons and protons are present in the nucleus of an atom whereas electrons are present in the orbits around the nucleus of the atom.  There are several shells in the orbital depending on the atomic number.  The electrons which are present in the outermost shell are said to be valence electrons.

They can be determined by the electronic configuration of the element.

The atomic number of strontium, Sr is 38. The electronic configuration of strontium, Sr is:

1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}

From the electronic configuration it is clear that the outermost shell of strontium, Sr is 5s. So, the number of valence electrons in strontium, Sr is 2.

Hence, there are 2 valence electrons in an atom of strontium (Sr).

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frez [133]
3KOH + H₃PO₄ ----> K₃PO₄ + 3H₂O
3 moles 1 mole


3 moles KOH ------ 1 mole H₃PO₄
X moles KOH ------ 1,56 mol
X = 3×1,56
X = 4,68 moles of KOH

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7 0
3 years ago
2. If 300.0 mL of a 2.5 M solution of nitric acid is added to 500.0 mL of water, what is the molarity of the
Afina-wow [57]

Answer:To calculate the Molarity of a 70 wt. % Nitric Acid the number of moles of HNO 3 present in 1 liter of acid needs to be calculated. Knowing the density of the acid to be 1.413 g/mL, we can calculate the weight of 1 L of 70% HNO 3 to be 1413

Explanation:

8 0
3 years ago
Which of the following is an example of a physical change?
dangina [55]
D it is only physical and not chemical
5 0
3 years ago
Read 2 more answers
Blance equation __CaBr2 (aq) + ___Li3PO4(aq) → ___Ca3(PO4)2(s) + ____LiBr (aq)
QveST [7]

Answer:

3CaBr2 + 2LI3PO4 - > Ca3(PO4) 2 + 6LiBr

Explanation:

The first one I did was PO4. There are two on the right side, so I added 2 to Li3PO4 on the other side. That balanced the PO4s and then gave me 6 Lithiums so I balanced that one next on the right side. I added 6 to LiBr which balanced the Li but then gave me 6 Br, so I finished it off by adding 3 in front of CaBr2 which balanced the calcium and bromines.

Here was the process:

CaBr2+2Li3PO4 -> Ca3(PO4)2+LiBr

Balances PO4 (2on both sides)

CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr

Balances Lithiums (6 on each side)

3CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr

Balances Calciums and Bromines (3 Calciums and 6 Bromines each side)

Hope this helped!

4 0
4 years ago
How does the chemical formula for the sulfite ion differ from the chemical formula for the sulfate ion?
VLD [36.1K]

Answer:

Sulfite contains 3 oxygens and sulfate contains 4 oxygens

Explanation:

6 0
3 years ago
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