Answer:
Explanation:
Angular speed of hoop ω = v / r
= 8.90 / .27
= 32.96 rad / s
Translational kinetic energy = 1/2 mv²
= .5 x 1.8 x 8.9²
= 71.29 J
Rotational kinetic energy = 1/2 Iω²
= 1/2 mR²x ω²
= 1/2 mv²
= 71.29 J
Total kinetic energy
= 2 x 71.29
= 142.58 J
This energy will be used to attain height
If h be the height attained
mgh = 142.58
h = 142.58 / mg
= 142.58 / 1.8 x 9.8
= 8.08 m .
Answer:
D
Explanation:
I think the answer is D, because of hallucinations
True
Because resistance= voltage/current
when current is constant and voltage increases, resistant increases
The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.
Explanation:
The magnetic field strength at the center of a current-carrying circular loop is
where
is the vacuum permeability
I is the current
R is the radius of the loop
For the first circular loop, we have
The second loop has
(same current)
(twice the radius)
So, the magnetic field at the centre of the second loop is
So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.
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The initial temperature of the metal bolt is 80.8 °C
We'll begin by calculating the heat absorbed by the water.
- Mass of water (M) = 0.15 Kg
- Initial temperature (T₁) = 21 °C
- Final temperature (T₂) = 25 °C
- Change in temperature (ΔT) = T₂ – T₁ = 25 – 21 = 4 °C
- Specific heat capacity of water (C) = 4184 J/KgºC
Q = MCΔT
Q = 0.15 × 4184 × 4
Q = 2510.4 J
Finally, we shall determine the initial temperature of the metal bolt.
- Heat absorbed by water = 2510.4 J
- Heat released by metal (Q) = –2510.4 J
- Mass of metal (M) = 0.050 Kg
- Final temperature (T₂) = 25 °C
- Specific heat capacity of metal (C) = 899 J/Kg°C
- Initial temperature (T₁) =?
Q = MC(T₂ – T₁)
–2510.4 = 0.050 × 899 (25 – T₁)
–2510.4 = 44.95 (25 – T₁)
Clear bracket
–2510.4 = 1123.75 – 44.95T₁
Collect like terms
–2510.4 – 1123.75 = –44.95T₁
–3634.15 = –44.95T₁
Divide both side by –44.95
T₁ = –3634.15 / –44.95
T₁ = 80.8 °C
Thus, the initial temperature of the metal is 80.8 °C.
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